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Aleksandr [31]
2 years ago
14

Using filtering as a strategy to deal with information overload requires Group of answer choices reviewing all unsolicited infor

mation presented. determining what information you may need and what information merits attention. using Wikipedia to verify information. disconnecting from sources of information completely. requesting references for all undocumented information.
Computers and Technology
1 answer:
STALIN [3.7K]2 years ago
4 0

Answer:

The answer is "Choice B"

Explanation:

Please find the complete question in the attached file.

A filter is a tool for removing undesirable parts. Eliminate solid from a fluid, for example. The filter may mean the filter action: it could be used as a verb. When the filter is mentioned, various branches of science and technology often refer to a certain type of device. Filtering tries to decide the data you need and the data you have to address the overload.

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Write a class called Course that represents a course taken at a school. Represent each student using the modified Student class
Vinvika [58]

Answer:

The code is given below with its appropriate output

Explanation:

//Student.java

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Student {

public String firstName;

public String lastName;

public float[] marks;

Scanner scanner = new Scanner(System.in);

public Student(String firstName, String lastName) {

this.firstName = firstName;

this.lastName = lastName;

}

public void getdetail() {

System.out.println("enter only five marks");

marks = new float[5];

int count = 0;

for (int i = 0; i < 5; i++) {

float mark = 0;

++count;

if (count <= 5) {

System.out.println("enter score " + count);

mark = scanner.nextFloat();

if (mark >= 0.0 && mark <= 100.0)

marks[i] = mark;

else {

System.out.println("you entered mark is invalid");

marks[i] = 0;

}

} else

System.out.println(" maximum is five only");

}

}

public void tostring() {

System.out.println("firstname :" + "\t" + firstName + "\t" + "lastname :"

+ "\t" + lastName + "\n" + "the marks are");

int count = 0;

for (float mark : marks) {

count++;

System.out.println("the mark of " + count + " is " + mark);

}

}

public void Averagecal() {

float sum = 0.0f;

for (float mark : marks) {

sum = sum + mark;

}

float avg = sum / 5;

System.out.println("average of a student is " + avg);

}

}

//Course.java

import java.io.*;

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Course {

public String courseName;

public int number;

Student[] students;

Scanner scanner = new Scanner(System.in);

public Course(String courseName) {

this.courseName = courseName;

}

public void addStudents() {

System.out

.println("how many no of students you want to add for this particular course");

int count = scanner.nextInt();

students = new Student[count];

for (int i = 0; i < count; i++) {

System.out.println("enter the first name");

String fname = scanner.next();

System.out.println("enter the last name");

String lname = scanner.next();

Student s = new Student(fname, lname);

s.getdetail();

s.tostring();

s.Averagecal();

students[i] = s;

}

}

public void roll() {

int count = 0;

for (Student stud : students) {

count++;

}

System.out.println("the no of students in this " + courseName

+ " course is " + count);

}

}

//Driver.java

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Driver {

public static void main(String[] args) {

Course course = new Course("java");

course.addStudents();

course.roll();

}

}

<u>output: </u>

C:\Users\Daniel\Desktop\New folder>javac Student.java

C:\Users\Danie;\Desktop\New folder>javac Course.java

C:\Users\Daniel\Desktop\New folder>javac Driver.java

C:\Users\Daniel\Desktop\New folder>java Driver

how many no of students you want to add for this particular course ?

1

enter the first name

john

enter the last name

rich

enter only five marks

enter score 1

89

enter score 2

91

enter score 3

85

enter score 4

78

enter score 5

96

firstname : john lastname : rich

the marks are

the mark of 1 is 89.0

the mark of 2 is 91.0

the mark of 3 is 85.0

the mark of 4 is 78.0

the mark of 5 is 96.0

average of a student is 87.8

the no of students in this java course is 1

C:\Users\Ravi\Desktop\New folder>

3 0
3 years ago
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