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igomit [66]
1 year ago
8

Lianne has some dimes and nickels with a total value of $4.60. The number of dimes she has is 4 more than 3 times the number of

nickels. How many nickels does she have?
I need the equation to solve this problem thanks
Mathematics
1 answer:
Annette [7]1 year ago
6 0

If Lianne has some dimes and nickels with a total value of $4.60. The number of dimes she has is 4 more than 3 times the number of nickels then 0.15 Nickels does Lianne has.

<h3>What is Equation?</h3>

Two or more expressions with an Equal sign is called as Equation.

Given,

Lianne has some dimes and nickels with a total value of $4.60.

The number of dimes she has is 4 more than 3 times the number of nickels.

We need to find number of nickels

From the given information

N+D=4.60

D=3N+4

N+3N+4=4.60

4N=4.60-4

4N=0.6

Divide both sides by 4

N=0.15

Hence, 0.15 Nickels does Lianne has.

To learn more on Equation:

brainly.com/question/10413253

#SPJ1

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Answer:

y = 2x + 10

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y = mx + c ( m is the slope and c the y- intercept )

Here m = 2, thus

y = 2x + c ← is the partial equation

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If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
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