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dimaraw [331]
3 years ago
13

There are 130 people in a sport centre. 73 people use the gym. 62 people use the swimming pool. 58 people use the track. 22 peop

le use the gym and the pool. 29 people use the pool and the track. 25 people use the gym and the track. 11 people use all three facilities. Given that a randomly selected person uses at least two facilities, what is the probability they use all the facilities?
Mathematics
1 answer:
Delvig [45]3 years ago
3 0

Answer:

\frac{11}{87}

Step-by-step explanation:

Total number of people = 130

Number of people who use the gym = 73

Number of people who use the pool = 62

Number of people who use the track = 58

Number of people who use the gym and the pool = 22

Number of people who use the pool and the track = 29

Number of people who use the gym and the track = 25

Number of people who use all three facilities = 11

Total number of people who use at least two facilities = 22 + 29 + 25 + 11 = 87

The probability that the randomly selected person uses all three facilities = number of those who use all three facilities ÷ total number of people who use at least two facilities.

==> 11 ÷ 87

==> \frac{11}{87}

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Write an equation in slope-intercept form of the line shown.
7nadin3 [17]

Answer:

y = 2x - 5

Step-by-step explanation:

Find the slope using the points, (1, -3) and (3, 1):

slope(m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 -(-3)}{3 - 1} = \frac{4}{2} = 2

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Find the y-intercept (b) by substituting x = 1, y = -3, and m = 2 in y = mx + b

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If a right triangle has a hypotenuse of length 20 units and one leg of length 16 units, find the length of the other leg. A. 12
xxTIMURxx [149]

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12

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c is hypotenuse and a and b are the legs

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Read 2 more answers
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Hello!

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Range: 6 to 14 pounds

Formula of density function:

y = 1/Range

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f(x) = 0.125

1)

P(x = 7)

A uniform distribution is a continuous distribution, so the probability of x being an EXACT value is approximately 0.

<u>This is the same as if we took the following integral. (Finding the area under a curve with the same start and end point)</u>
\int\limits^a_a {f(x)} \, dx  = 0

Therefore, P(x = 7) = 0.

2)
We can think of this as finding the area of a rectangle.

The width would be the difference between 8.25 pounds and 12 pounds:
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The height would be the function (y = .125), or:
h = .125

Using the equation for the area of a rectangle: (A = h * w)

A = 3.75 * .125 = 0.469

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3)
To find the probability GREATER than 10.50 pounds, we can subtract this value from the max value for the width:
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Solve for the area:
A = 3.50 * .125 = 0.4375

P(x > 10.5) = 0.4375

5 0
2 years ago
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