1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dimaraw [331]
3 years ago
13

There are 130 people in a sport centre. 73 people use the gym. 62 people use the swimming pool. 58 people use the track. 22 peop

le use the gym and the pool. 29 people use the pool and the track. 25 people use the gym and the track. 11 people use all three facilities. Given that a randomly selected person uses at least two facilities, what is the probability they use all the facilities?
Mathematics
1 answer:
Delvig [45]3 years ago
3 0

Answer:

\frac{11}{87}

Step-by-step explanation:

Total number of people = 130

Number of people who use the gym = 73

Number of people who use the pool = 62

Number of people who use the track = 58

Number of people who use the gym and the pool = 22

Number of people who use the pool and the track = 29

Number of people who use the gym and the track = 25

Number of people who use all three facilities = 11

Total number of people who use at least two facilities = 22 + 29 + 25 + 11 = 87

The probability that the randomly selected person uses all three facilities = number of those who use all three facilities ÷ total number of people who use at least two facilities.

==> 11 ÷ 87

==> \frac{11}{87}

You might be interested in
You make $10.50 an hour at your part-time job and Andy makes $9.75 an hour at his full-time job. If you work a full week of 40 h
Marianna [84]
The awnser is $420.00 (10.50 X 40 = 4200)
7 0
2 years ago
There are 30 students in a class that took a test. The average grade of 10 students was 80. The other 20 students average was 89
Vsevolod [243]
10 students averaged 80, so the sum of their scores was (10 x 80) = 800

20 students averaged 89, so the sum of their scores was (20 x 89) = 1,780

All together, the sum of all 30 scores was (800 + 1,780) = 2,580

30 students totaled 2,580, so their average was  (2,580 / 30)  = <em> 86</em> .
6 0
3 years ago
Help please I don’t know the answer and I’m like late soo
icang [17]
It’s the first one!
8 0
3 years ago
Read 2 more answers
_________ are defined as lines that never have one point in common.
barxatty [35]

Answer:

The correct option is option number 4. Parallel lines are defined as lines that never have one point in common.

Step-by-step explanation:

Parallel lines: Parallel lines are the lines that will never cross each other. As they never meet, so they won't have a common point.

On the other hand, the other options are incorrect. This is because,

Perpendicular lines: Perpendicular lines are the lines that make 90 degrees angle with each other.

Skew lines: Skew lines are the lines that are not present on the same plane.

Coplanar lines: Any lines which are known to occur on the same plane are termed as coplanar lines.

4 0
3 years ago
Convert from rectangular to polar coordinates: note: choose rr and θθ such that rr is nonnegative and 0≤θ&lt;2π0≤θ&lt;2π (a)(9,0
DochEvi [55]

Answer:

Step-by-step explanation:

Convert rectangle (x , y) to polar coordinates ( r , θ)

x=r  \cos \theta, y= r \sin \theta

r=\sqrt{x^2+y^2} , \theta =tan^-^1 (\frac{y}{x} )

a) converts (9, 0) to polar coordinates  ( r , θ)

r=\sqrt{x^2+y^2} \\\\=\sqrt{9^2+0} \\\\=9

\theta= \tan^-^1 (\frac{0}{9} )\\\\=0

b) Convert (18,\frac{18}{\sqrt{3} } ) to polar coordinates ( r, θ)

r = \sqrt{18^2+(\frac{18}{\sqrt{3} })^2 } \\\\=\sqrt{324+108} \\\\=\sqrt{432}

\frac{x}{y} \theta = \tan^-^1(\frac{\frac{18}{\sqrt{3} } }{18} )\\\\= \tan ^-^1(\frac{1}{\sqrt{3} } )\\\\= \frac{\pi}{6}

c)  converts (-5, 5) to polar coordinates  ( r , θ)

r =\sqrt{(-5)^2+(5)^2} \\\\=\sqrt{50} \\\\=5\sqrt{2}

\theta=\tan^-^1(\frac{5}{-5} )\\\\= \tan^-^1(-1)\\\\=\frac{3\pi}{4}

d)  converts (-1, √3) to polar coordinates  ( r , θ)

r=\sqrt{(-1)^2+(\sqrt{3})^2 } \\\\= \sqrt{4} \\\\=2

\theta=\tan^-^1(\frac{\sqrt{3} }{-1} )\\\=\tan^-^1(-\sqrt{3} )\\\\=\frac{2\pi}{3}

= \frac{2\pi}{\sqrt{3} }

6 0
3 years ago
Other questions:
  • Margie received her store order on 12/3/16 at 4AM. She just opened one of the
    14·1 answer
  • How many different rotational symmetries does a square have?​
    15·2 answers
  • 0.4859 as a fraction
    13·2 answers
  • Simplify the expression:<br> 10x<br> +<br> 7x<br> +<br> 6x
    5·2 answers
  • 3x + 4y =10 6x -2y = 40
    5·1 answer
  • Which of the following is not a form of bias? Multiple Choice Portions of the population are excluded or underrepresented from t
    5·1 answer
  • How many 1/4can go in 1/8
    13·2 answers
  • 1/2x^2-x-4=0 (PLEASE GIVE REAL ANSWER)
    6·1 answer
  • If sin theta equals to a divided by b what is the value of sec square theta minus tan square theta
    8·1 answer
  • Does x - 6 = 2 (4x + 3) have
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!