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GuDViN [60]
3 years ago
14

Pythagorean Theorem

Mathematics
1 answer:
allsm [11]3 years ago
3 0

Answer:

Perimeter = 40.9544511501

Area = 142.407864951

Step-by-step explanation:

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Solve this equation using elimination: 4x-y=8;6x+y=2
fomenos
Solve simultaneously.

4x - y = 8
6x + y = 2


Multiply top equation by 6, and bottom equation by 4, to eliminate x, so that we can find y.
~
24x - 6y = 48
24x - 4y = 8

Subtract top from bottom to form one equation.
~
-2y = 40
Therefore y is 20.

Put y back in to an equation, such as 4x - y = 8.
~
4x - 20 = 8
4x = 28
x = 7
7 0
4 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
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 the answer is irrational

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3 years ago
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nlexa [21]

the angle would be 180

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Margaret [11]
AZL is the correct answer
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