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2 years ago

A line has a slope of Negative one-half and a y-intercept of –2.What is the x-intercept of the line?

Mathematics

1 answer:

lys-0071 [83]2 years ago

3 0

Answer:

The x intercept would be -4

Step-by-step explanation:

First, get your numbers into slope intercept form, y = mx + b. This would be y = -1/2x - 2. Then, replace y for 0, which would be 0 = -1/2x - 2. Add 2 on both sides to get 2 = -1/2x. then, multiply each side by -2, you end up with -4 = x, which means -4 is your x intercept.

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2 years ago

7/12 - □ = 1/6<br><br><br>□ = ________

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2 years ago

Jamie received £26 pocket money last week. He spent it as follows: 10% on sweets, 25% on magazines 15% on games How much did Jam

navik [9.2K]

Answer:

Total money left with Jamie = £13

Step-by-step explanation:

Jamie received pocket money = £26

He spent on sweets = 10% of total pocket money

Expense on magazines = 25% of the total money

Expense on games = 15% of the pocket money

Total expenditure on sweets, magazines and games = $\frac{10}{100}+\frac{25}{100}+\frac{15}{100}$

= $\frac{50}{100}$ Or 50% of the pocket money he received

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2 years ago

How do you use distributive property on s+0.08s?

Ivanshal [37]

Answer:

s(1+.08)

Step-by-step explanation:

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3 years ago

Read 2 more answers

(b) If a series follows geometric progression, show that the ratio of the sum of term to the sum from (n+1) term to (2n) term is

Nadusha1986 [10]

Proof with explanation:

We know that the sum of first 'n' terms of a Geometric progression is given by

$S_{n}=\frac{a(1-r^{n})}{1-r}$

where

a = first term of G.P

r is the common ratio

'n' is the number of terms

Thus the sum of 'n' terms is

$S_{n}=\frac{a(1-r^{n})}{1-r}$

Now the sum of first '2n' terms is

$S_{2n}=\frac{a(1-r^{2n})}{1-r}$

Now the sum of terms from $(n+1)^{th}$ to $(2n)^{th}$ term is $S_{2n}-S_{n}$

Thus the ratio becomes

$\frac{S_{n}}{S_{2n}-S_{n}}\\\\=\frac{\frac{a(1-r^{n})}{1-r}}{\frac{a(1-r^{2n})}{1-r}-\frac{a(1-r^{n})}{1-r}}\\\\=\frac{1-r^{n}}{r^{n}-r^{2n}}\\\\=\frac{1-r^{n}}{r^{n}(1-r^{n})}\\\\=\frac{1}{r^{n}}$

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2 years ago