Answer:
<em>First.</em> Let us prove that the sum of three consecutive integers is divisible by 3.
Three consecutive integers can be written as k, k+1, k+2. Then, if we denote their sum as n:
n = k+(k+1)+(k+2) = 3k+3 = 3(k+1).
So, n can be written as 3 times another integer, thus n is divisible by 3.
<em>Second. </em>Let us prove that any number divisible by 3 can be written as the sum of three consecutive integers.
Assume that n is divisible by 3. The above proof suggest that we write it as
n=3(k+1)=3k+3=k + k + k +1+2 = k + (k+1) + (k+2).
As k, k+1, k+2 are three consecutive integers, we have completed our goal.
Step-by-step explanation:
Answer:
the answer is c
Step-by-step explanation:
its the only one that makes sense
Answer:
1.1
Step-by-step explanation:
Write out a long division problem! Since you can't have a decimal in the divisor, multiply both numbers by 10. This will leave you with 39.6÷36. Now all you have to do is follow the steps and end up with an answer of 1.1
All fractions that are less than 1/2 but more than 0.
The inequality is 0>1/2
