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Anon25 [30]
3 years ago
8

M∠LONm, angle, L, O, N is a straight angle.

Mathematics
1 answer:
Ne4ueva [31]3 years ago
5 0

Answer: 41

Step-by-step explanation:

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You forget the last two digits of your password for a website.
Degger [83]
1/81 chance of getting the two digits
Suppose what
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Determine the slope of a line that goes through (2,7) and (11,10)
tia_tia [17]

Answer:

1/3

Use the slope formula and simply the fraction.

4 0
3 years ago
Draw line segment AB - 7cm and bisect it using compass.​
Fed [463]

Answer:

<h2>Your answer is in picture.</h2><h3>Steps of construction: </h3>

(i) Draw a line segment AB = 7 cm.

(ii) With A as centre and radius more than half of AB, draw arcs, one on each side of AB.

(iii) With B as centre and same radius as before, draw arcs, cutting the previously drawn arcs at X and Y respectively.

(iv) Now join XY, meeting AB at O.

Thus, XY is the perpendicular bisector of AB.

Step-by-step explanation:

Hope it is helpful....

6 0
3 years ago
Find the solution to m^2+9m=0
sladkih [1.3K]
<h3>Answers:  m = 0 or m = -9</h3>

Work Shown:

m^2+9m=0

m(m+9)=0

m = 0 or m+9 = 0

m = 0 or m = -9

For more information, check out the topics about factoring and the zero product property.

5 0
2 years ago
Read 2 more answers
We want to factor the following expression: 25x^2−36y^8 We can factor the expression as (U+V)(U-V) where U and V are either cons
Aneli [31]

Answer:

U=5\,x

V=6\,y^4

Step-by-step explanation:

Recall that an expression that can be factored as (U+V)(U-V) using distributive property for multiplication of binomials, should render:  U^2-V^2 (the factorization given above is that of a difference of squares. Then, the idea is to write the original expression :

25\,x^2-36\,y^8

as a difference of perfect squares. Let's examine each term and its numerical and variable form to find if they can be written as perfect squares:

a) the term   25\,x^2=5^2\,x^2=(5x)^2 therefore, if we assign the letter U to 5\,x, the first term becomes:

25\,x^2=(5\,x)^2=U^2

b) the term   -36\,y^8=-6^2\,(y^4)^2=-(6\,y^4)^2  therefore, if we assign the letter V to  6\,y^4 , this second term becomes:

-36\,y^8=-(6\,y^4)^2=-V^2

With the above identification, our expression can now be factored as a difference of squares:

25\,x^2-36\,y^8=(5\,x)^2-(6\,y^4)^2=U^2-V^2=(U+V)(U-V)

5 0
3 years ago
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