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3 years ago

Which of the following is an irrational number?

Mathematics

2 answers:

RSB [31]3 years ago

7 0

D. Square Root of 80

serg [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Only perfect squares can be rational numbers. the square root of 80 is the only one that is not a perfect square.

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Fifteen seventh graders were randomly selected to see how many pushups in a row they could do. Their data are shown. a. b. 45, 4

GuDViN [60]

Answer: Median = 42

Mean = 43.8

Step-by-step explanation:

When we have a data set of n points {x₁, x₂, ..., xₙ}

The mean is written as:

(x₁ + ... + xₙ)/N

And the median will be the value in the middle of the data set.

So first, let's write our data set in order, from least to greatest.

{36, 36, 38, 40, 40, 40, 42, 42, 43, 45, 45, 48, 48, 70}

So we have 14 values.

The middle value will be at:

(n + 1)/2

(14 + 1)/2 = 7.5

Now, counting from the left, we have that the 7.5th value is 42. (the 7th value is 42, and the 8th value is 42)

So the median is 42.

Now the mean:

M = (36 + 36 +38 +40+40+40+ 42 +42 + 43 + 45 + 45 + 48 + 48 + 70)/14

M = 43.8

8 0

3 years ago

Plz answer 4-8 if possible, I have been struggling

Fed [463]

It’s -4 because when you take 4 out of 8 then you still have another 4 to take away to you go into the negatives and have the answer -4

6 0

3 years ago

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Using the zero product property solve for the x values given (3x-2)(x+1)=0.

RSB [31]

Answer:

{2/3 ; -1}

Step-by-step explanation:

IF THIS ANSWER HELPS YOU, PLEASE MARK IT AS BRAINLIEST!

7 0

3 years ago

Read 2 more answers

Learning Activities

igomit [66]

Step-by-step explanation:

answers I the above photo

some of the questions are not clear

8 0

3 years ago

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An incomplete distribution is given below:Variable You are given that the median value is 70 and the total number of items is 20

expeople1 [14]

Answer:

The missing frequencies are x = 8 and y = 43.

Step-by-step explanation:

Median Value =70

Then the median Class =60-80

Let the missing frequencies be x and y.

Given: Total Frequncy = 200 , Median = 46

$\left|\begin{array}{c|ccccccc}Value&0-20&20-40&40-60&60-80&80-100&100-120&120-140\\Frequency&12&30&x&66&y&27&14\\$Cumu.Freq&12&42&42+x&108+x&108+x+y&135+x+y&149+x+y\end{array}\right|$

From the table

$\sum f_i =149+x+y$

Here, n = 200

n/2 = 100

Lower Class Boundary of the median class, l=60

Frequency of the median class(f) =66

Cumulative Frequency before the median class, f=42+x

Class Width, h=10

$Median = l + \dfrac{\dfrac{n}{2} - c.f }{f} \times h$

$70 = 60+ \dfrac{100- 42+x }{66}\times 10\\70 = 60+ \dfrac{58+x }{66}\times 10\\70-60=\dfrac{58+x }{66}\times 10\\10*66=10(58+x)\\58+x=66\\x=66-58\\x=8$

200=149+x+y

200=149+8+y

y=200-(149+8)

y=43

Hence, the missing frequencies are x = 8 and y = 43.

8 0

3 years ago