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Alona [7]
3 years ago
14

It would be nice if y’all helped me out

Mathematics
1 answer:
Elena-2011 [213]3 years ago
3 0

Answer: 0

Step-by-step explanation:

Slope is rise/run so if the y value is stagnant (10 in this case) then the line is horizontal and has no slope

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Sophie [7]
1. sin<span> (30°) = 1/2; 2. </span>sin<span> (300°) = - 3/2; 3. tan (30°) = 3/3; </span>4<span>. </span>sin<span> (45°) = 2/2; 5. sec (</span><span>240°) = -2; </span>6<span>. </span>sin<span> (</span>60<span>°) = 3/2; 7. </span>cos<span> (45°) = 2/2: Start a new line. 8. </span>cos<span> ... 17. tan (</span>150<span>°) = - 3/3; 18. </span>csc<span> (30°) = 2; 19. </span>csc<span> (45°) = 2; 20. </span>sec<span> (</span>210<span>°) = -2 3/3: Start a new line. 21. </span>cot<span> (45°) = 1; 22. sec (45°) = 2; 23. </span>sin<span> (330°) = -1/2; </span>24<span>. tan (135°) = -1 ...</span>
8 0
3 years ago
Find the first term and common ratio for the geometric sequence a2=-15 a4=-375
DedPeter [7]

The first term and common ratio for the geometric sequence are -3 and 5 respectively

<h3>Geometric sequence</h3>

This are sequence that increases exponentially. The nth term of the sequence is given as:

Tn = ar^n-1

where;

a is the first term

r is the common ratio

n is the number of terms

ar = -15

ar^3 = -375

Divide

r^2 = 375/15

r^2 = 25

r = 5

Determine the first term

a= -15/r

a = -15/5

a = -3

Hence the first term and common ratio for the geometric sequence are -3 and 5 respectively

Learn more on sequence here: brainly.com/question/6561461

#SPJ1

3 0
2 years ago
Find the inverse of function f.<br> f(x) = 1/3 - 1/21x
monitta
F^-1(x)= - 1/7(3x-1)
8 0
3 years ago
Pleasee help me with this…. Tyyyy
san4es73 [151]

Answer:

16.3

Step-by-step explanation:

x/41 = 23/58, 58x = 943, x = 16.3

5 0
2 years ago
Read 2 more answers
Can you please help me ​
denis23 [38]

Answer:

very bottom

Step-by-step explanation:

the one with "a number or quantity that when multiplied with another produces a given number or expression. "

4 0
3 years ago
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