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Elan Coil [88]
2 years ago
15

If a bank has total deposits of $7,200 and reserves of $1,600: instructions: round to the nearest whole number. (a) what is its

current reserve ratio? 5 incorrect % (b) how large is its loan portfolio (outstanding loans)? 88 incorrect %
Mathematics
1 answer:
Serjik [45]2 years ago
4 0
A.) The current reserve ratio is given by the fraction of the bank's total deposits held in reserves.
Given that the bank's total deposits is $7,200 and the reserves is $1,600, the current reserve ratio is given by:

\frac{1,600}{7,200} \times100\%=22\%.


b.) The loan portfolio is given by (total deposit - reserves) / total deposits

Thus, the loan portfolio of the given bank is given by:

\frac{7,200-1,600}{7,200} \times100\%= \frac{5,600}{7,200} \times100\% \\  \\ =78\%
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ANSWER

See attachment.

EXPLANATION

The given function is

y = {x}^{2} + 4x + 5

When we compare this function to

y = a{x}^{2} + bx + c

We have a=1, b=4 and c=5

We put this inside the formula for the discriminant, which is

D = {b}^{2} - 4ac

D = {4}^{2} - 4(1)(5)

D = 16 - 20 = - 4

Since the discriminant is negative, the function has no x-intercepts.

The graph of this function is the one hanging in the air above the x-axis and opens upwards.

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3 years ago
Find the solution of the system of equation 2x+2y=2 5x+4y=2
Soloha48 [4]

Answer:

(-2,3)

Step-by-step explanation:

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2 years ago
Which of the following situations are equal to 90%? Select all that apply. A) 18 out of 24 B) 18 out of 20 C) 36 out of 40 D) 54
ArbitrLikvidat [17]

Answer:

b, c, d, e

Step-by-step explanation:

a) 18/24 = 75%

b) 18/20 = 90%

c) 36/40 = 90%

d) 54/60 = 90%

e) 81/90 = 90%

8 0
2 years ago
What are the solutions to the equation <br><img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%20625" id="TexFormula
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3 0
3 years ago
Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
Tasya [4]

Answer:

\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]

Step-by-step explanation:

Given function:

y =\ln(\frac{(6 - x)^{\frac{3}{2}}}{x^{\frac{2}{3}}})

we know

\ln(\frac{A}{B}) = ln(A) - ln(B)

thus,

y = \ln((6 - x)^{\frac{3}{2}}) - \ln(x^{\frac{2}{3}})

or

also,

ln(Aⁿ) = n × ln(A)

thus,

y = (\frac{3}{2})\times\ln(6 - x) - (\frac{2}{3})\times\ln(x)

therefore,

\frac{dy}{dx}=[(\frac{3}{2})\times\frac{1}{(6-x)}\times(0 - 1)] - [ (\frac{2}{3})\times\frac{1}{x}\times1]

or

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or

\frac{dy}{dx}=-[(\frac{3(3x)+2\times2(6-x)}{2(6-x)\times(3x)})]

or

\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]

5 0
3 years ago
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