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Sholpan [36]
3 years ago
10

Let's assume that the smallest possible message is 64 bytes (including the 33-byte overhead). if we use 100base-t, how long (in

meters) is a 64-byte message? while electricity in the cable travels a bit slower than the speed of light, once you include delays in the electrical equipment in transmitting and receiving the signal, the effective speed is only about 40 million meters per second. (hint: first calculate the number of seconds it would take to transmit the frame then calculate the number of meters the signal would travel in that time, and you have the total length of the frame.)
Computers and Technology
1 answer:
Ostrovityanka [42]3 years ago
3 0

As we know that 10-bAse data travels at the rate of 10 mbps, therefore at 1 sec we have 10240 bytes.

We have to calculate for 64 bytes travelling in one second. Multiply both sides by 64.

64 sec = 10240 x 64 bytes

64 bytes = 64 / 10240 sec

Now we have to calculate for light of speed

1 sec = 186000 miles

Substitute this value to the formula above

64 bytes = 64 / 10240 x 1 sec = 64 / 10240 x 186000 miles = 64 / 10240 x 186000 x 5280 feet = 6138x10^3 feet

Therefore, 64 bytes is equal to 6138 x 10^3 feet long message

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Which of the following is a form of security protection that protects individual files by scrambling the contents in such a way
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Damage to which portion of the limbic system results in loss of memory of recent events and difficulty committing anything new t
Vera_Pavlovna [14]

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Hippocampus.

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8 0
3 years ago
Write a program that reads a file name from the keyboard. The file contains integers, each on a separate line. The first line of
Sindrei [870]

Answer:

Explanation:

import java.util.Scanner;

import java.io.*;

public class ArrayProcessing

{

public static void main(String[] args) throws IOException

{

Scanner kb = new Scanner(System.in);

String fileName;

System.out.print("Enter input filename: ");

fileName = kb.nextLine();

File file = new File(fileName);

if(!file.exists())

{

System.out.println("There is no input file called : " + fileName);

return;

}

int[] numbers = inputData(file);

printArray(numbers);

}

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{

Scanner inputFile = new Scanner(file);

int index = 1;

int size = inputFile.nextInt();

int[] values = new int[size];

while(inputFile.hasNextInt() && index < values.length)

{

values[index] = inputFile.nextInt();

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inputFile.close();

return values;

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int count = 1;

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4 0
4 years ago
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Answer:

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7 0
3 years ago
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