The value of result of the code segment is executed is known to be 4.
<h3>Why is the value of the code segment so?</h3>
When the result of is not executed because the condition is said to be false and also when there is a false condition is, the else statement will be said to be true
Therefore, result = result + 2; -> result is brought up by 2 to bring about 4 and as such, the value of result of the code segment is executed is known to be 4.
Learn more about scores from
brainly.com/question/19492935
#SJ1
Answer:
When working with cloud computing, drive failures and need for usage and data is easily identifiable, so in short term, all of the things that show the user/s what needs to be done is the characteristic.
Explanation:
Answer:
A game is built from a combination of sub-tasks in order to provide the best experience to the user and make sure that the interface is comprises of only the results of the ongoing sub-tasks to provide a higher degree of data abstraction.
Data abstraction refers to the process of representing the essential information without including the background details. Rolling a dice is preferred to be a sub-task so that the user only gets to know about the result of the roll and does not have to wait for or anticipate the result. Moreover, a game may consist of n number of sub-tasks so it is not a good idea to include them in the main framework and are preferred to be abstracted.
Answer:
public class Digits
{
public static boolean allDigitsOdd(int num)
{
boolean flag=true;
int rem;
while(num>0)
{
rem=num%10;
num=num/10;
if(rem%2==0) // if a even digit found immediately breaks out of loop
{
flag=false;
break;
}
}
return flag; //returns result
}
public static void main(String args[])
{
System.out.println(allDigitsOdd(1375)); //returns true as all are odd digits
}
}
OUTPUT :
true
Explanation:
Above program has 2 static methods inside a class Digits. Logic behind above function is that a number is divided by 10 until it is less than 0. Each time its remainder by 0 is checked if even immediately breaks out of the loop.
<span> the new way of </span>removing duplicates<span> from an iterable while keeping it in the original order </span>