Answer:
Step-by-step explanation:
y=(x+5)2−1
Use the vertex form,
y=a(x−h)2+k, to determine the values of a, h, and .a=1h=−5k=−1Find the vertex(h,k(−5,−1)
We are given
△ABC, m∠A=60° m∠C=45°, AB=8
Firstly, we will find all angles and sides
Calculation of angle B:
we know that sum of all angles is 180
m∠A+ m∠B+m∠C=180
we can plug values
60°+ m∠B+45°=180
m∠B=75°
Calculation of BC:
we can use law of sines
now, we can plug values
Calculation of AC:
now, we can plug values
Perimeter:
we can plug values
Area:
we can use formula
now, we can plug values
...............Answer
Answer:
2
Step-by-step explanation:
The tangent is positive in quadrants I and III. There are two angles with that tangent value:
33.96° and 213.69°
Answer:
No, it' snot a solution
Step-by-step explanation:
x − 2 ≥ −1.6
x - 2 + 2 ≥ -1.6 + 2
x ≥ 0.4
Answer:
First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)
To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0 x=-4 x=2
So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)
And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5
3 gets us 21
So now you know end behavior, zeroes, and signs of intervals
Hope this helps
