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Sati [7]
3 years ago
13

What's the answer PLZZZ HELP the topic btw is reasoning in math

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
6 0

3 + 4x - 3x = 4 is given

3 + x = 4 is combine like terms (4x and -3x were combined to 1x)

x = 1 is subtraction property of equality (3 was subtracted from both sides of the equation)

balandron [24]3 years ago
3 0

Answer:

1. given

2.combine like terms

3. subtraction property of equality

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What’s the answer?????
posledela

Answer:9

Step-by-step explanation: x+4=13

x=13-4

x=9

3 0
3 years ago
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What fraction is represented by the portion of the figure that is NOT shaded? (2 out of 10 are shaded)
OverLord2011 [107]

Well let's see.

If the figure is split up into 10 pieces, then
each piece is  1/10  of the whole figure.

If  2  of the pieces are shaded, then
2/10  of the whole figure is shaded.

How many pieces are left ?

There were 10 pieces all together, and
2 of them are shaded.  Hmmm.  I think
there are probably  (10 - 2) = 8  of them left
that are not shaded.

8 pieces makes  8/10  of the whole figure.

8 0
3 years ago
Find the number described. What number is 16​% of 70​?
photoshop1234 [79]

Answer:

58.8

Step-by-step explanation:

multiply 16% by 70 then substract your answer by 70

4 0
3 years ago
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a used truck for $4,500 he made an agreement with the dealer to put $1,500 and make payments of 350 for the next 10 months that
Aneli [31]
Ist amount paid = $1500
Making $350 for 10 months = 10*350 = $3500
Total amount paid  = 1500 + 3500 = 5000
So an amount of $5000 was paid to cover the cost of $4500 within the ten month period.
I = PRT
Interest, I = 5000 - 4500 = 500Time, t = 10 months = 10/12 = (5/6) year.Principal P = 4500
R = I /(PT)  R = 500 / (4500*5/6)
R = (500*6) / (4500*5)
R = 0.1333..
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3 0
3 years ago
The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
nexus9112 [7]

Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c

2000=-\frac{24000}{3}+c

2000=-8000+c

c=10,000

Therefore, E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

8 0
2 years ago
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