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inessss [21]
3 years ago
13

An electric field greater than about 3×106V/m causes air to break down (electrons are removed from the atoms and then recombine,

emitting light). If you shuffle along a carpet and then reach for a doorknob, a spark flies across a gap you estimate to be 1mm between your finger and the doorknob.
Estimate the voltage between your finger and the doorknob.
Physics
2 answers:
Artist 52 [7]3 years ago
5 0

Answer:

Voltage, V = 3000 volts

Explanation:

Given that,

Electric field, E=3\times 10^6\ V/m

The gap between your finger and the doorknob is 1 mm

We need to find the voltage between your finger and the doorknob. We know that the relation between voltage and electric field is given by :

V=E\times d

V=3\times 10^6\ V/m\times 0.001\ m

V = 3000 volts

So, the voltage between your finger and the doorknob is 3000 volts. Hence, this is the required solution.

Orlov [11]3 years ago
3 0
Could be about 3kV from the data shown in q
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A boulder of mass 2000. kg breaks loose of a mountainside and plunges 200. m straight down into a lake at a temperature of 5.00◦
natka813 [3]

Answer:

DS = 13865.7[J/K]

Explanation:

We can calculate the energy of the rock, like the potential energy relative to the lake level. Which can be calculated by means of the following expression of the potential energy:

E_{p}=m*g*h\\\\where:\\m = mass = 2000[kg]\\h = elevation = 200 [m]\\g = gravity = 9.81[m/s^2]

Therefore:

E_{p}=2000*9.81*200\\E_{p}=3924000 [J]\\

This energy is transformed into thermal energy.

we shall remember that isothermal heat transfer processes are internally reversible, so the entropy change of a system during one of these processes can be determined, by the following expression.

DS=\frac{Q}{T}\\ where:\\DS = entropy change [J/K]\\Q = Heat transfer [J]\\T = temperature [K]

T = 5 + 278 = 283[K]

DS = 3924000 / 283

DS = 13865.7[J/K]

5 0
4 years ago
Objects A and B are separated by 2m and the force of attraction between them is 8 x 10^-10 N . If the mass of A is 8kg what is t
Jobisdone [24]

Answer:

Only object a and b???????

5 0
3 years ago
A small 12.00g plastic ball is suspended by a string in a uniform, horizontal electric field with a magnitude of 10^3 N/C. If th
tensa zangetsu [6.8K]

Answer:

The net charge is 67.89 \mu C

Solution:

As per the question:

Mass of the plastic bag, m = 12.0 g = 12.0\times 10^{-3}\ kg

Magnitude of electric field, E = 10^{3}\ N/C

Angle made by the string, \theta = 30^{\circ}

Now,

To calculate the net charge, Q on the ball:

Vertical component of the tension in the string, T = Tcos\theta

Horizontal component of the tension in the string, T = Tsin\theta

Now,

Balancing the forces in the x-direction:

Tsin\theta = QE

Q = {Tsin\theta}{E}                             (1)

Balancing the forces in the y-direction:

Tcos\theta = mg

where

g = acceleration due to gravity = 9.8\ m/s^{2}

Thus

T = \frac{mg}{cos\theta }

T = \frac{12.0\times 10^{-3}\times 9.8}{cos30^{\circ}} = 0.1357\ N

Use T = 0.1357 N in eqn (1):

Q = {0.1357\times sin30^{\circ}}{10^{3}} = 6.789\times 10^{- 5}\ C

Q = 67.89\times 10^{- 5}\ C = 67.89\mu C

7 0
4 years ago
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