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2 years ago

In the reaction 2Ca + O2 → 2CaO for every 2 Ca you will need how much O2?

Physics

1 answer:

Serjik [45]2 years ago

5 0

Answer:

Explanation: that is the ratio

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The larger the push, the larger the change in velocity. This is an example of Newton's Second Law of Motion which states that th

Mars2501 [29]

Answer:

According to Newton's 2nd law

The force acting on a body produces acceleration in its direction which is directly propotional to the force but inversly propotinal to the mass of tbe body.

Explanation:

a = F/m

F = ma

Where( F) is force (m) is mass and (a) is acceleration.

6 0

3 years ago

Are small molecular units joined together in large molecules

inysia [295]

<span>Polymers are small molecular units joined together in large molecules.

hope this helps!</span>

7 0

3 years ago

A ball is dropped from a tall bridge of height 48 m. What will the speed of the ball be immediately before it hits the ground, i

soldi70 [24.7K]

Answer:

2700

Explanation:

because calculate the minute1=60×45=2700

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3 years ago

Read 2 more answers

An ore car of mass 39000 kg starts from rest and rolls downhill on tracks from a mine. At the end of the tracks, 19 m lower vert

cupoosta [38]

Answer:

The compression in the spring is 5.88 meters.

Explanation:

Given that,

Mass of the car, m = 39000 kg

Height of the car, h = 19 m

Spring constant of the spring, $k=4.2\times 10^5\ N/m$

We need to find the compression in the spring in stopping the ore car. It can be done by balancing loss in gravitational potential energy and the increase in elastic energy. So,

$mgh=\dfrac{1}{2}kx^2$

x is the compression in spring

$x=\sqrt{\dfrac{2mgh}{k}} \\\\x=\sqrt{\dfrac{2\times 39000\times 19\times 9.8}{4.2\times 10^5}} \\\\x=5.88\ m$

So, the compression in the spring is 5.88 meters.

6 0

3 years ago

Increasing which two things would increase gravitational potential energy?

sukhopar [10]

Answer:

Mass and height

Explanation:

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about $9.8 m/s2.$

Which is represented as;

$PE_g=mgh$

$PE_g$ stands for gravitational potantial energy,

m stands for mass of object,

g is the gravitational constant and

h is the height.

Here we see that mass of object and height is directly proportional to the gravitational potential energy.

That means increasing in mass and height will result in increasing gravitational potential energy.

7 0

3 years ago