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Whitepunk [10]
3 years ago
12

When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. Suppose anot

her bomb is tested, and 1.5 grams of matter are converted into energy. How many joules of energy are released by the explosion?
Physics
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

The value is E =  1.35 *10^{14} \ J

Explanation:

From the question we are told that

    The mass of matter converted to energy on first test is  m  =  1 \  g  = 0.001 \  kg

    The mass of matter converted to energy on second test m_1 =  1.5 \  g = 1.5 *10^{-3} \ kg

    Generally the amount of energy that was released by  the explosion is  mathematically  represented as  

         E =  m * c^2

=>       E =  1.5 *10^{-3}  * [ 3.0 *10^{8}]^2

=>       E =  1.35 *10^{14} \ J

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The speed of light in a transparent medium is 0.6 times that of its speed in vacuum. Find the refractive index of the medium.
grin007 [14]
<h2>Answer:</h2>

The refractive index is 1.66

<h2>Explanation:</h2>

The speed of light in a transparent medium is 0.6 times that of its speed in vacuum .

Refractive index of medium = speed of light in vacuum / speed of light in medium  

So

RI = 1/0.6 = 5/3 or 1.66

3 0
3 years ago
Read 2 more answers
Based on its type of chemical bond, which of the following has the highest boiling point?
Sever21 [200]
<h3><u>Answer;</u></h3>

Potassium chloride

<h3><u>Explanation;</u></h3>
  • Potassium Chloride is an ionic compound and has ionic bond which is stronger than covalent bond in ethyl alcohol,water ,ammonia, and thus has the highest boiling point .
  • ionic bond is a type of bond that results from the transfer of electrons between metallic atoms and non-metallic atoms.
5 0
3 years ago
2. A 1.54 kΩ resistor is connected to an AC voltage source with an rms voltage of 240 V.
svp [43]

(a) The maximum potential difference across the resistor is 339.41 V.

(b) The maximum current through the resistor is 0.23 A.

(c) The rms current through the resistor is 0.16 A.

(d)  The average power dissipated by the resistor is 38.4 W.

<h3>Maximum potential difference</h3>

Vrms = 0.7071V₀

where;

  • V₀ is peak voltage

V₀ = Vrms/0.7071

V₀ = 240/0.7071

V₀ = 339.41 V

<h3> rms current through the resistor </h3>

I(rms) = V(rms)/R

I(rms) = (240)/(1,540)

I(rms) = 0.16 A

<h3>maximum current through the resistor </h3>

I₀ = I(rms)/0.7071

I₀ = (0.16)/0.7071

I₀ = 0.23 A

<h3> Average power dissipated by the resistor</h3>

P = I(rms) x V(rms)

P = 0.16 x 240

P = 38.4 W

Learn more about maximum current here: brainly.com/question/14562756

#SPJ1

8 0
2 years ago
Earl travels 50m east in 10 minutes and later 100m north in 15 minutes. What is her total displacement?all travels 50 m East in
xxMikexx [17]

Answer:

111.8 m

Explanation:

Displacement is the change in position of an object. The SI unit of displacement is the meters. The displacement of an object can be calculated by determining the shortest distance from the starting point to the end point.

Since earl travels 50 m east and then 100 m north, let x represent the displacement. Therefore x is the shortest distance from starting to end. Earl movement forms a right angled triangle with x as the hypotenuse. Hence:

x² = 50²  + 100²

x² = 12500

x = 111.8 m

3 0
3 years ago
Consider an infinetly long hollow cylindrical wire. The wire has an outer diameter b and the clindrical hole at its center has d
Nadusha1986 [10]

Answer:

B = (μ₀*i/(2*π*x))*(x²-(a/2)²)/((b/2)²-(a/2)²)

Explanation:

Given

Outer diameter of the wire = b  ⇒ R = b/2

Diameter of the clindrical hole at the center = a  ⇒ r = a/2

The current that flows from left to right and is uniformly spread over the region between a and b = i

We apply Ampere's Law

Using the following formula for  a/2 ≤ x ≤ b/2

B = (μ₀*i/(2*π*x))*(x²-(a/2)²)/((b/2)²-(a/2)²)

6 0
3 years ago
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