<h2>Answer:</h2>
The refractive index is 1.66
<h2>Explanation:</h2>
The speed of light in a transparent medium is 0.6 times that of its speed in vacuum
.
Refractive index of medium = speed of light in vacuum / speed of light in medium
So
RI = 1/0.6 = 5/3 or 1.66
<h3><u>Answer;</u></h3>
Potassium chloride
<h3><u>Explanation;</u></h3>
- Potassium Chloride is an ionic compound and has ionic bond which is stronger than covalent bond in ethyl alcohol,water ,ammonia, and thus has the highest boiling point .
- ionic bond is a type of bond that results from the transfer of electrons between metallic atoms and non-metallic atoms.
(a) The maximum potential difference across the resistor is 339.41 V.
(b) The maximum current through the resistor is 0.23 A.
(c) The rms current through the resistor is 0.16 A.
(d) The average power dissipated by the resistor is 38.4 W.
<h3>Maximum potential difference</h3>
Vrms = 0.7071V₀
where;
V₀ = Vrms/0.7071
V₀ = 240/0.7071
V₀ = 339.41 V
<h3> rms current through the resistor </h3>
I(rms) = V(rms)/R
I(rms) = (240)/(1,540)
I(rms) = 0.16 A
<h3>maximum current through the resistor </h3>
I₀ = I(rms)/0.7071
I₀ = (0.16)/0.7071
I₀ = 0.23 A
<h3> Average power dissipated by the resistor</h3>
P = I(rms) x V(rms)
P = 0.16 x 240
P = 38.4 W
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Answer:
111.8 m
Explanation:
Displacement is the change in position of an object. The SI unit of displacement is the meters. The displacement of an object can be calculated by determining the shortest distance from the starting point to the end point.
Since earl travels 50 m east and then 100 m north, let x represent the displacement. Therefore x is the shortest distance from starting to end. Earl movement forms a right angled triangle with x as the hypotenuse. Hence:
x² = 50² + 100²
x² = 12500
x = 111.8 m
Answer:
B = (μ₀*i/(2*π*x))*(x²-(a/2)²)/((b/2)²-(a/2)²)
Explanation:
Given
Outer diameter of the wire = b ⇒ R = b/2
Diameter of the clindrical hole at the center = a ⇒ r = a/2
The current that flows from left to right and is uniformly spread over the region between a and b = i
We apply Ampere's Law
Using the following formula for a/2 ≤ x ≤ b/2
B = (μ₀*i/(2*π*x))*(x²-(a/2)²)/((b/2)²-(a/2)²)