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snow_tiger [21]

4 years ago

10

The power needed to operate your body is about 100 watts. Suppose a human body (of typical mass) could run on fusion power and c

ould convert 0.8 % of its mass into energy. Part A How much energy would be available through fusion?

1 answer:

dem82 [27]4 years ago

8 0

Answer:

$5.04\times10^{16}$ J of energy is available through fusion .

Explanation:

let us consider weight of the human body on an average be 70 kg .

since 0.8% of mass is used to convert into energy = $70\times \frac{0.8}{100} =0.56kg$

since according to einstein mass energy equation

$E=MC^{2}$

$E=0.56\times 9\times10^{16}\\ =5.04\times10^{16}J$

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An object is thrown straight up into the air with an initial speed of 8 m/s, and reaches a greatest height of 15 m before it fal

Ugo [173]

Answer:

The value is $T_t = 2.5659 \ s$

Explanation:

From the we are told that

The initial speed of the object is $u = 8 \ m/s$

The greatest height it reached is $h = 15 \ m$

Generally from kinematic equation we have that

$v^2 = u^2 + 2gH$

At maximum height v = 0 m/s

So

$0^2 = 8^2 + 2 * - 9.8 * H$

=> $H = 3.27 \ m$

Here H is the height from the initial height to the maximum height

So the initial height is mathematically represented as

$s = h - H$

=> $s = 15 - 3.27$

=> $s = 11.73 \ m$

Generally the time taken for the object to reach maximum height is mathematically evaluated using kinematic equation as follows

$v = u + (-g) t$

At maximum height v = 0 m/s

$0 = 8 - 9.8t$

=> $t = 0.8163 \ s$

Generally the time taken for the object to move from the maximum height to the ground is mathematically using kinematic equation as follows

$h = ut_1 + \frac{1}{2} gt_1^2$

Here the initial velocity is 0 m/s given that its the velocity at maximum height

Also g is positive because we are moving in the direction of gravity

So

$15 = 0* t + 4.9 t^2$

=> $t_1 = 1.7496$

Generally the total time taken is mathematically represented as

$T_t = t + t_1$

=> $T_t = 0.8163 + 1.7496$

=> $T_t = 2.5659 \ s$

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Hope I helped! :)

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