Answer:
57.5
Step-by-step explanation:
The expected frequency of West Campus and Failed :
Let :
Failed = F
East Campus = C
West Campus = W
Passed = P
Frequency of FnW :
[(FnE) + (FnW) * (PnW) + (FnW)] / total samples
[(52 + 63) * (63 + 37)] / 200
[(115 * 100)] / 200
11500 / 200
= 57.5
n(Failed n East campus)
This question is worded weirdly, but it means:
8 / (5/2)
= 8 * (2/5)
= 16/5
All in the tenths place after the decimal.
1. Distribute the 6 to the 2x and the -11
12x-22+15=3x+12
2. Combine like terms
12x-7=3x+12
9x=+19
x=19/9
Part B x=19/9