Answer:
Step-by-step explanation:
trapezium
<h2>If the diagonals of a quadrilateral divide each other proportionally, then prove that the quadrilateral is a trapezium.</h2>
Answer:
7
Step-by-step explanation:
1. Lets Combine Like Terms. The only combineable terms are 8 and 8. So if we combine them they will equal 16. And we will have (2n+2)=16
2. Let's isolate the variable. We can do this by subtracting 2 from both sides. This will come out to 2n+14.
3. Let's further isolate the variable. We can do this by dividing both sides by two, which will finally come out to n=7
(2•7)-5
14-5= 9
So the answer is 9
Answer:
- 1 = pentagon
- 2 = diamond
- 3 = square
- 5 = circle
- 6 = rectangle
- 7 = oval
- 8 = triangle
- 9 = hexagon
- 10 = trapezoid
Step-by-step explanation:
Each half of a hanger divides the total weight in half. The right-most vertical has a total weight of 80/16 = 5. It consists of a square and a diamond, and we know the square is 1 more than the diamond. That means 2 diamonds weigh 5 -1 = 4. A diamond weighs 2, and a square weighs 3. The other half of that balance is a circle, which weighs 5.
The total of a square and oval is 10, so the oval is 10 -3 = 7. The two trapezoids weigh 20, so each is 10.
The second vertical from the left is a circle and diamond which will weigh 5+2 = 7. That makes the sum of a pentagon and rectangle also be 7. The 7+7 = 14 below the square on the left branch makes the total of that branch be 14+3 = 17, which is also the sum of the triangle and hexagon.
The weight below the rectangle at top left is 17+17 = 34, and the weight of that entire branch is 40. Thus the rectangle is 40-34 = 6, which makes the pentagon 7-6 = 1.
We require the sum of the triangle and hexagon be 17, with the triangle being the smaller value, and both being 9 or less (the trapezoid is the only figure weighing more than 9). Hence the triangle is 8 and the hexagon is 9.
The weights are summarized in the answer section, above.
