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Vaselesa [24]
3 years ago
7

A 3-phase stepping motor is to be used to drive a linear axis for a robot. The motor output shaft will be connected to a screw t

hread with a screw pitch of 1 mm. We want to be able to have a spatial control of at least 0.05 mm. a)How many poles should the motor have?
Chemistry
1 answer:
Gre4nikov [31]3 years ago
8 0

Answer:

The  number of poles is 12.

Explanation:

The step angle is given by

\phi=\frac{360^{\circ}}{N}

Where

\phi_1 is the step angle

To Find the Step angle of the Stator

\phi_1=\frac{360^{\circ}}{N_s}

Where

\phi_1  is the step angle

N_s is the number of poles or teeth on stator

To Find the Step angle of the Rotor

\phi_2=\frac{360^{\circ}}{N_r}

where

\phi_2  is the step angle

N_r is the number of poles or teeth on rotor

In the question it is stated that

N_s+ N_r = \frac{1}{0.05}

N_s+ N_r = 20

Selecting N_s= 12 and N_r= 8  

\phi = \phi_2 -\phi_1  

=\frac{(360^{\circ})}{8}- \frac{(360^{\circ})}{12}

=45^{\circ}-30^{\circ}  

=15^{\circ}

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Can you please help me with this??
tensa zangetsu [6.8K]
In balancing chemical equations, all you need to do is make it so that you have the same number of each element on both sides of the eqtn (if I have 5C on the left, I have to have 5C on the right — an element can’t magically appear or disappear); that being said:

(2)C2H6 + 7O2 ➡️ 6H2O + 4CO2

(12)HClO4 + P4O10 ➡️ 4H3PO4 + (6)Cl2O7

2N2 + (5)O2 + 2H2O ➡️ 4HNO3

(3)CaCl2 + 2Na3PO4 ➡️ (1)Ca3(PO4)2 + 6NaCl

4FeS + 7O2 ➡️ 2Fe2O3 + 4SO2


3 0
4 years ago
g The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g) SO2(g) + Cl2(g) is first order in SO2Cl2 with a rate const
Alex_Xolod [135]

Answer : The concentration of SO₂Cl₂ after 720 min will be, 3.81\times 10^{-4}M

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 2.80\times 10^{-3}\text{ min}^{-1}

t = time passed by the sample  = 720 min

a = initial amount of the reactant  = 2.86\times 10^{-3}M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

720=\frac{2.303}{2.80\times 10^{-3}}\log\frac{2.86\times 10^{-3}}{a-x}

a-x=3.81\times 10^{-4}M

Therefore, the concentration of SO₂Cl₂ after 720 min will be, 3.81\times 10^{-4}M

5 0
3 years ago
Which element in period 4 would have chemical properties similar to magnesium? 7. which metalloids would have chemical propertie
azamat
The only solution you'll need to have for this problem is a periodic table. The columns in the table are called groups, and they are number from the left to the right starting with 1. The rows in the table are called periods which are numbered from the top to bottom starting with 1. 

6. Elements that belong to the same group portray similar chemical properties. Therefore, the element in period 4 which is also in group 2 is <em>Calcium (Ca)</em>.

7. The elements that are striked through with the red slanting lines are the metalloids. All the elements to the left of the metalloids are metals. All the elements to the right are nonmetals. Bromine has a symbol of Br. Since At is a metalloid and located in the same group with Br, the <em>answer is Astatine (At).</em>

8. Tin has the chemical symbol of Sn. The nonmetal that is located in the same group is <em>Carbon (C)</em>.

9. All the elements in period 6 would have similar properties. The answers could be: <em>Phosphorus (P), Arsenic (As), Antimony (Sb) and Bismuth (Bi)</em>.

10. Period is row 1 and group 18 is the last column. <em>The answer is Helium (He).</em>

5 0
3 years ago
Read 2 more answers
What mass of caco3 (in grams) is needed to make 10.5 l of a 1.50 m caco3 solution?
kiruha [24]
Data:

M = 1.50 (assiming the data is Molarity and not molality, which is written with capital letter)

V= 10.5 l

n = ?

Formulas:

M = n / V => n = M * V

n = mass in grams / molar mass => mass in grams = n * molar mass

Solution

n = 1.50 * 10. 5 l = 15.75 moles

molar mass CaCO3 = 40.08 g/mol + 12.01 g/mol + 3* 16 g/mol = 100.09 g/mol

mass in grams = 15.75 moles * 100.09 g/mol = 1,576.4 g.

Answer: 1,576 g
4 0
3 years ago
78.9 + 890.43 - 21 = 9.5 x 10^2
maria [59]

948 or 9.48 x 10^2

There are two sets of rules for significant figures

• One set for addition and subtraction

• Another set for multiplication and division

You used the set for multiplication and division.

This problem involves addition and subtraction, and the rule is

The number of places after the decimal point in the answer must be <em>no greater than the number of decimal places in every term</em> in the sum.

Thus, we have

78.9

+890.43

-21.

= 948.33

The "21" term has the fewest digits after the decimal point (none), so the answer must have no digits after the decimal point.

To the correct answer is 948 = 9.48 x 10^2. It has three significant figures.

8 0
4 years ago
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