Question

g The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g) SO2(g) + Cl2(g) is first order in SO2Cl2 with a rate constant of 2.80×10-3 min-1. If the initial concentration of SO2Cl2 is 2.86×10-3 M, the concentration of SO2Cl2 will be M after 720 min have passed.

Answer 1

Answer : The concentration of SO₂Cl₂ after 720 min will be, $3.81\times 10^{-4}M$

Explanation :

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant  = $2.80\times 10^{-3}\text{ min}^{-1}$

t = time passed by the sample  = 720 min

a = initial amount of the reactant  = $2.86\times 10^{-3}M$

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$720=\frac{2.303}{2.80\times 10^{-3}}\log\frac{2.86\times 10^{-3}}{a-x}$

$a-x=3.81\times 10^{-4}M$

Therefore, the concentration of SO₂Cl₂ after 720 min will be, $3.81\times 10^{-4}M$