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ivolga24 [154]
3 years ago
9

Which of the following observations indicates that an atom has neutrons?

Chemistry
2 answers:
olganol [36]3 years ago
8 0

Answer:

The correct answer is C: A radiation consisting of uncharged particles is emitted when alpha particles strike beryllium atoms.

Explanation:

Chadwick discovered neutron while experimenting with a gold foil. A stream of alpha particles produced from a polonium source was directed at beryllium target. It was noticed that some penetrating radiations were produced. These uncharged particles were called neutrons because on the charge detector these particles showed no deflection.

Their nuclear reaction is as follow.

                             ₂He + ₄Be ----------> ₀n + ₆C

Chadwick noticed that neutrons cannot ionize gases and are highly penetrating particles.

-Dominant- [34]3 years ago
4 0

Answer: C. A radiation consisting of uncharged particles is emitted when alpha particles strike beryllium atoms.

A. Some uncharged particles are scattered by a beryllium atom when it hits a gold foil.

B. Some uncharged particles bounce back from a gold foil when it is bombarded with alpha particles.

C. A radiation consisting of uncharged particles is emitted when alpha particles strike beryllium atoms.

D. A radiation which attracts electrons is produced when a beryllium atom is bombarded with alpha particles.

Explanation:

I just took the test and the answer is C. A radiation consisting of uncharged particles is emitted when alpha particles strike beryllium atoms.

Good Luck!!

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How many moles of aluminum oxide al2o3 are in a sample with a mass of 204.0
erik [133]

Answer:

2 moles

Explanation:

Let us first start by calculating the molecular mass of Al₂O₃.

The mass of a mole of any compound is called it's molar mass. 1 molar mass 6.02 X 10²³, or Avogadro's number, of compound entities.

Say, 1 mole of Al₂O₃ has 6.02 X 10²³ of Al₂O₃ molecules/atoms. It also has 2*6.02 X 10²³ number of Al atoms and 3*6.02 X 10²³ number of O atoms.

Molecular mass of Al : 26.981539 u

Molecular mass of O: 15.999 u

Therefore, molecular mass of Al₂O₃ is:

= (2*26.981539) + (3*15.999) u

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This can be approximated to 102 u.

1mole weighs 102 u

So, 2moles will weigh 2*102 = 204 u

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