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ivolga24 [154]
3 years ago
9

Which of the following observations indicates that an atom has neutrons?

Chemistry
2 answers:
olganol [36]3 years ago
8 0

Answer:

The correct answer is C: A radiation consisting of uncharged particles is emitted when alpha particles strike beryllium atoms.

Explanation:

Chadwick discovered neutron while experimenting with a gold foil. A stream of alpha particles produced from a polonium source was directed at beryllium target. It was noticed that some penetrating radiations were produced. These uncharged particles were called neutrons because on the charge detector these particles showed no deflection.

Their nuclear reaction is as follow.

                             ₂He + ₄Be ----------> ₀n + ₆C

Chadwick noticed that neutrons cannot ionize gases and are highly penetrating particles.

-Dominant- [34]3 years ago
4 0

Answer: C. A radiation consisting of uncharged particles is emitted when alpha particles strike beryllium atoms.

A. Some uncharged particles are scattered by a beryllium atom when it hits a gold foil.

B. Some uncharged particles bounce back from a gold foil when it is bombarded with alpha particles.

C. A radiation consisting of uncharged particles is emitted when alpha particles strike beryllium atoms.

D. A radiation which attracts electrons is produced when a beryllium atom is bombarded with alpha particles.

Explanation:

I just took the test and the answer is C. A radiation consisting of uncharged particles is emitted when alpha particles strike beryllium atoms.

Good Luck!!

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How many grams of Co are needed to react with an excess of fe203 to produce 156.2 g FE? show your work.
Gekata [30.6K]

The reaction is given as

Fe2O3 (s)+ 3CO(g)--->3CO2(g)+ 2Fe(s)

No.of moles=mass in gram/molar mass

As for Fe mole =156.2g/55.847=2.7969~2.797

The ratio b/w CO and Fe is 3:2

Moles of CO needed= 2.797x3/2=4.1955

Mass of CO needed= 4.195mol x 28.01g/mol= 117.515g

8 0
3 years ago
How many pounds of ice are required to absorb 4900 kJ of heat as the ice melts? The heat of fusion of water is 0.334 kJ/g.
Goshia [24]

Answer:

m = 32.34 pounds of ice.

Explanation:

In this case we need to use the following expression of heat:

q = m * ΔHf   (1)

Where:

q: heat absorbed in J or kJ

m: mass of the compound in g

ΔHf: heat of fusion of the water in kJ/g

We are asked to look for the mass of ice in pounds, so after we get the grams, we need to convert the grams to pounds, using the following conversion:

1 pound --------> 453.59 g   (2)

So, we have the heat and heat of fusion, from (1) let's solve for the mass, and then, using (2) the conversion to pounds:

q = m * ΔHf  

m =  q / ΔHf

m = 4900 / 0.334 = 14,670.66 g of ice

Now, the conversion to pounds:

m = 14,670.66 g * 1 pound/453.59 g

<h2>m = 32.34 pounds of ice.</h2>

Hope this helps  

5 0
2 years ago
What is the wavelength of light with 2.89 x 10-19 J of energy? (The speed of
Alika [10]

Let's see

\\ \rm\rightarrowtail E=hv

\\ \rm\rightarrowtail E=\dfrac{hc}{\lambda}

  • lambda is wavelength
  • h is Planck constant
  • c is velocity of sound in air
  • E in energy

\\ \rm\rightarrowtail \lambda=\dfrac{hc}{E}

\\ \rm\rightarrowtail \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{2.89\times 10^{-19}}

\\ \rm\rightarrowtail \lambda=6.878\times 10^{-7}m

\\ \rm\rightarrowtail \lambda=68.8\mu m

3 0
1 year ago
How many grams are contained in a 0.183 mol sample of ammonium phosphate?
soldi70 [24.7K]

Molar mass of ( NH₄)₃PO₄ = 14.01×3 + 1.01×12 + 30.97 + 16.00×4 = 149.12 g/mol. Mass of 0.183 mol ...

7 0
2 years ago
Consider a 0.10 M aqueous benzoic acid, CeHeCOOH. The K benzoic acid. 6.5 x 10 for A) Write a balanced equation that shows the r
7nadin3 [17]

Answer:

a) C6H5COOH + H2O ↔ H3O+  +  C6H5COO-

b) [ H3O+ ] = 2.517 E-3 M

c) pH = 2.599

Explanation:

a) balanced equation:

C6H5COOH + H2O ↔ H3O+  +  C6H5COO-

⇒ Ka = ( [ H3O+ ] * [ C6H5COO- ] ) / [ C6H5COOH ] = 6.5 E-5

mass balance:

0.10 m = [ C6H5COO- ] + [ C6H5COOH ].....(1)

charge balance:

[ H3O+ ] = [ C6H5COO- ] + [ OH- ] .......[ OH- ] : comes from water, it's not significant

⇒ [ H3O+ ] = [ C6H5COO- ] .........(2)

b) (2) in (1):

⇒ 0.10 M = [ H3O+ ] + [ C6H5COOH ]

⇒ [ C6H5COOH ] = 0.10 - [ H3O+ ]

⇒ Ka = [ H3O+ ]² / ( 0.1 - [ H3O+ ] ) = 6.5 E-5

⇒ [ H3O+ ]² + 6.5 E-5 [ H3O+ ] - 6.5 E-6 = 0

⇒ [ H3O+ ] = 2.517 E-3 M

c) pH = - log [ H3O+ ]

⇒ pH = - Log ( 2.517 E-3 )

⇒ pH = 2.599

7 0
3 years ago
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