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QveST [7]
2 years ago
11

Determine the mass of the following samples (remember mass => grams)

Chemistry
1 answer:
kakasveta [241]2 years ago
5 0

Mass is the amount of content available in the matter. The mass of the moles of samples given are

2 moles Co = 117.86 g Co

5 moles H2 =  10.10 g  H₂

2.1 moles H₂O = 37.84 g  H₂O

<h3>What is a mole?</h3>

A  mole can be atoms or molecules or ions or any substance.

The mass of one mole of Co is 58.93 g.

Then, 2 moles of Co will be 2 x 58.93 g = 117.86 g Co

The mass of one mole of H₂ is 2.02 g.

Then, 5 moles of  H₂ will be 5 x 2.02 g =  10.10 g  H₂

The mass of one mole of H₂O is 18.02 g .

Then, 2.1 moles of  H₂O will be 2.1 x 18.02 g =  37.84 g  H₂O

Thus, the mass of the following samples in grams

2 moles Co = 117.86 g Co

5 moles  H₂=  10.10 g  H₂

2.1 moles H₂O = 37.84 g  H₂O

Learn more about mole.

brainly.com/question/26416088

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How many grams of water can be produce from the complete reaction of excess nitric acid and 33.2 mL of 0.245 M lithium hydroxide
Mariulka [41]

Mass of water produced : 0.146 g

<h3>Further explanation</h3>

Given

33.2 mL of 0.245 M lithium hydroxide

Required

mass of water

Solution

Reaction

HNO₃ (aq) + LiOH (aq) → H₂O (l) + LiNO₃ (aq)

mol LiOH :

= M x V

= 0.245 x 33.2 ml

= 8.134 mmol

From the equation, the mol ratio of HNO₃ : H₂O = 1 : 1, so mol H₂O = 8.134 mmol

mass H₂O :

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3 0
2 years ago
Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. W
nikklg [1K]

Answer:

There are 3 steps of this problem.

Explanation:

Step 1.

Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.

Step 2.

Enthalpy of saturated liquid Haq = 781.124 J/g

Enthalpy of saturated vapour Hvap = 2779.7 J/g

Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g

Step 3.

In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy

So, H1=H2

     H2= (1-x)Haq+XHvap.........1

    Putting the values in 1

    2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}

                        = 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)

1904.976 (J/g) = x1998.576 (J/g)

                     x = 1904.976 (J/g)/1998.576 (J/g)

                     x = 0.953

So, the quality of the wet steam is 0.953

                   

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marin [14]

Answer:

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Explanation:

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