<span><span>Given the equation of a circle"<span>x^2 + y^2 - 4x +6y -36 = 0</span>We will use completing the square method to rewrite the equation into the form:(x-a)^2 + (y-b)^2 = r^2 where (a,b) is the center and r is the radius.Let us rewrite the terms.==> x^2 - 4x + y^2 + 6y = 36Now we will complete the square for both x^2 ands y^2.We will add [( coefficient of x)/2]^2 and [(coefficients of y)/2]^2 to both sides.Then we will add :(4/2)^2 = 2^2 = 4(6/2)^2 = 3^2 = 9Then we will add 4 and 9 to both sides.==> x^2 - 4x +4 + y^2 + 6y + 9 = 36 + 4 + 9==> (x-2)^2 + (y+3)^2 = 49==> (x-2)^2 + (y+3)^2 = 7^2Now we will compare the equation withe the standard form of a circle.Then we conclude that:<span>The center of the circle is: ( 2, -3) and the radius is 7.</span></span></span>
To solve this you first need to turn your mixed numbers into improper fractions. to do this for 
you multiply the denominator (5) by the whole number (9) to get 45 and then add that to the numerator (4) to get your new fraction 
.
You repeat this process with 
to get 
.
Now that you have two fractions you can multiply by the opposite reciprocal. To do this you flip the second fraction and change the division sign to a multiplication sign like so 
Then, you just multiply the fractions by multiplying the numerators to get 98 and multiplying the denominators to get 35.
Now, to simplify 
you first divide both the numerator and denominator by 7 to get 
.
Finally, you can take 10 out of the numerator to make 
Answer:
-1
Step-by-step explanation:
4x=-4
X = - 1
That's itt
