What is log5 (x) + 4 * log5 (y) - 2* log5 (z) simplified?

Mathematics

1 answer:

NISA [10]4 years ago

6 0

G = 0.81 -1 o -1 x -1

You might be interested in

Find the sum of -4a-3 and 7a-4.

Anna71 [15]

Answer: 3a - 7

Step-by-step explanation:

(-4a - 3) + (7a - 4)

Combine like terms

-4a + 7a - 3 - 4

3a - 7

Hope this helped!

7 0

3 years ago

Read 2 more answers

A line passes through A(3,7) and B(-4,9) find the value of a if C (a 1) is on the line

Xelga [282]

What we need to do first, is to write the equation of the line through points A and B.

the slope of the line through A(3, 7) and B(-4, 9) is

$m= \frac{9-7}{-4-3}= \frac{2}{-7}=- \frac{2}{7}$

the equation of the line is :

$y-7=- \frac{2}{7}(x-3)\\\\y-7=- \frac{2}{7}x+ \frac{6}{7}\\\\y= - \frac{2}{7}x+ \frac{6}{7}+ \frac{49}{7}\\\\y= - \frac{2}{7}x+ \frac{55}{7}$

C(a, 1) is on this line so it must satisfy the equation:

$y= - \frac{2}{7}x+ \frac{55}{7} \\\\1= - \frac{2}{7}a+ \frac{55}{7}\\\\ \frac{2}{7}a= \frac{48}{7}\\\\2a=48\\\\a=24$

3 0

3 years ago

PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! *EXTRA POINTS* DONT SKIP:((

marishachu [46]

Answer:

5/8

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A cowboy rode his horse 45 miles at 15 and then rode another 35 miles at 10 . How long did the ride last? A. 6 h B. 6.5 h C. 60

Mashutka [201]

You are given the distance of the horse of 45 miles at 15miles per hour and another 35 miles at 10 miles per hour. You are asked the total time in hours of the cowboy riding his horse. You have to get the time each mile the cowboy rode.

45 miles/15 miles per hour = 3 hours
35 miles/10 miles per hour = 3.5 hours
3 hours + 3.5 hours = 6.5 hours
 So the answer is B. 6.5 hours.

8 0

3 years ago

Read 2 more answers

PLS HELp! WILL MARK BRAINLIEST!! NEED HELP W BOX AND WHISKER PLOTS!

harina [27]

Answer:

1) Female

2) Male

Step-by-step explanation:

8 0

3 years ago