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liubo4ka [24]
2 years ago
14

A tall pea plant (TT) is crossbred with a short pea plant (tt). The Punnett square below shows the separated alleles for two pea

plants. Punnett square showing female parent across the top with a phenotype of tall and a genotype of TT and a male parent across the side with a phenotype of short and a genotype of tt. Inside the top left box 1 is written, inside the top right box 2 is written, inside the bottom left box 3 is written, inside the bottom right box 4 is written. Which of the following shows the correct match of the box numbers and the genotype of the offspring? 1 = TT; 2 = TT; 3 = Tt; 4 = Tt 1 = TT; 2 = Tt; 3 = Tt; 4 = tt 1 = TT; 2 = Tt; 3 = Tt; 4 = Tt 1 = Tt; 2 = Tt; 3 = Tt; 4 = Tt

Biology
2 answers:
daser333 [38]2 years ago
7 0

Answer:

The answer is Tt, Tt, Tt, Tt.

Explanation:

hope this helps :)

musickatia [10]2 years ago
6 0
Hi there! 

Using the image below, you can see that all of the boxes are Tt, or heterozygous. Therefore, 1 = Tt, 2 = Tt, 3 = Tt, and 4 = Tt.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

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Which is not a major difference in the organization or content of prokaryotic and eukaryotic genomes?
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Answer:

All of the above are true

Explanation:

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3 years ago
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3 years ago
A locus that affects susceptibility to a degenerative brain disease has two alleles, V and v. In a population, 16 people have ge
Pie

Answer:

Yes, the population is evolving

Explanation:

Hardy-Weinberg equilibrium states that a population is not evolving if it is in hardy weinberg equilibrium as the alleles frequency do not change over time in generations.

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In the question, since the observed genotype are-

P² - VV= 16

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q²- vv- 12

<u>1. Calculate allele frequency</u>

Now we will calculate if the expected value is same or close or not.

We will calculate allele frequency

Population has 120 individuals which means it has - 240 alleles.

In which V (p) will be- 32 +92= 124 allele

p- dominant allele/ total allele=  124/ 240 = 0.52

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<u>2. Expected genotype frequency</u>

Now we will calculate expected genotypic frequency.

P²- 0.52 X 0.52= 0.27

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<u>3. Expected progeny </u>

P²= 0.27 x 120= 32 VV

2Pq= 0.5 X 120= 60 Vv

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Since the observed value is not equal to the expected value therefore the population is not in Hardy- Weinberg equilibrium and the population is evolving.

Thus, Yes, the population is evolving is correct.

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