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alexandr1967 [171]
3 years ago
5

The greatest common factor of any two even numbers is always even. True or false and why?

Mathematics
1 answer:
alina1380 [7]3 years ago
3 0
Yes. Two even numbers are each divisible by 2. The GCF must therefore always have two as one of its factors; this makes it even.
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If 16 counters are 4/9, then what is the ONE?
notsponge [240]
36...

<span>divide your 16 by 4, so that you have 1/9. You then multiply the resulting number(4) by your denominator, 9. 4 times 9 = 36</span>
6 0
3 years ago
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In the above figure, m∠A = 32° and m∠B = (2x + 14)°. If angles A and B are complementary angles, what are the value of x and the
Neko [114]

Complementary angles have a sum of 90

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5 0
3 years ago
How are determinants used to find areas of polygons?
ANTONII [103]
When you arrange the N points in sequence around the polygon (clockwise or counterclockwise), the area is half the magnitude of the sum of the determinants of the points taken pairwise. The N determinants will also include the one involving the last point and the first one.

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4 0
3 years ago
ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?
MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = \sqrt{(x_2-x_1)^2 +( y_2-y_1)^2

Step 1: Finding the length of  EF

By using distance formula,

EF = \sqrt{(-7 - 0)^2 + (4-0)^2}

EF = \sqrt{(49) + (16)}

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Step 2: Finding the length of  FG

By using distance formula,

FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}

Step 2: Finding the length of  GE

GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8

Thus we could see that the sides EF = FG

So it is  a isosceles triangle.

6 0
3 years ago
Explain how 7/12 is greater than 1/3 but less than 2/3
Zepler [3.9K]
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6 0
3 years ago
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