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solniwko [45]
3 years ago
8

PLEEEEASE HELP!!!! QUICK

Mathematics
1 answer:
lana [24]3 years ago
5 0

Answer:

By 25% :)

Step-by-step explanation:

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Which of the tables represents a function?
svlad2 [7]

Answer:

a

Step-by-step explanation:

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3 years ago
After running 14 laps the runner had compleated 25% of the race. How many laps does he still have to compleate?
miss Akunina [59]

Answer:

42 laps

Step-by-step explanation:

7 0
2 years ago
The expression 10a+6c gives the cost (in dollars) for a adults and c children to eat at a buffet restaurant. A. The cost for 1 a
Liono4ka [1.6K]

Answer: The total cost is \$62 assuming the cost for 1 adult is \$5 and the cost for 1 child is \$2

Step-by-step explanation:

Assuming the cost for 1 adult is \$5 and the cost for 1 child is \$2:

a=\$5 and c=\$2

Then the expression that gives the total cost 10 a+6c is solved as:

10(\$5)+6(\$2)=\$62

4 0
3 years ago
Use lagrange multipliers to find the point on the plane x â 2y + 3z = 6 that is closest to the point (0, 2, 4).
Arisa [49]
The distance between a point (x,y,z) on the given plane and the point (0, 2, 4) is

\sqrt{f(x,y,z)}=\sqrt{x^2+(y-2)^2+(z-4)^2}

but since \sqrt{f(x,y,z)} and f(x,y,z) share critical points, we can instead consider the problem of optimizing f(x,y,z) subject to x-2y+3z=6.

The Lagrangian is

L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)

with partial derivatives (set equal to 0)

L_x=2x+\lambda=0\implies x=-\dfrac\lambda2
L_y=2(y-2)-2\lambda=0\implies y=2+\lambda
L_z=2(z-4)+3\lambda=0\implies z=4-\dfrac{3\lambda}2
L_\lambda=x-2y+3z-6=0\implies x-2y+3z=6

Solve for \lambda:

x-2y+3z=-\dfrac\lambda2-2(2+\lambda)+3\left(4-\dfrac{3\lambda}2\right)=6
\implies2=7\lambda\implies\lambda=\dfrac27

which gives the critical point

x=-\dfrac17,y=\dfrac{16}7,z=\dfrac{25}7

We can confirm that this is a minimum by checking the Hessian matrix of f(x,y,z):

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite (we see its determinant and the determinants of its leading principal minors are positive), which indicates that there is a minimum at this critical point.

At this point, we get a distance from (0, 2, 4) of

\sqrt{f\left(-\dfrac17,\dfrac{16}7,\dfrac{25}7\right)}=\sqrt{\dfrac27}
8 0
2 years ago
What is the correcr order of opperations ??
Dahasolnce [82]

Step-by-step explanation:

Plus,Minus,Times and divide

+,-,×,÷

4 0
3 years ago
Read 2 more answers
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