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3 years ago

Explain why the two argon atoms are attracted to each other.

1 answer:

5 0

Each are non-metals, which form a covalent bond. They also have high electron rapport.
- nonmetal and nonmetal equals covalent bond.

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A 0.1375-g sample of solid magnesium is burned in a constant-volume bomb calorimeter that has a heat capacity of 3024 J/°C. The

Anna35 [415]

Answer:

-24.76 kJ/g; -601.8 kJ/mol

Explanation:

There are two heat flows in this experiment.

Heat from reaction + heat absorbed by calorimeter = 0

q1 + q2 = 0

mΔH + CΔT = 0

Data:

m = 0.1375 g

C = 3024 J/°C

ΔT = 1.126 °C

Calculations:

0.1375ΔH + 3024 × 1.126 = 0

0.1375ΔH + 3405 = 0

0.1375ΔH = -3405

ΔH = -24 760 J/g = -24.76 kJ/g

ΔH = -24.76 kJ/g ×24.30 g/mol = -601.8 kJ/mol

3 0

3 years ago

Please help me asap

Masja [62]

Answer: With the first quarter moon, the Moon is "waxing", which means getting larger. with the third quarter moon, the Moon is "waning", which means getting smaller.

Explanation: In each case, the Moon is half lit ---- first quarter moon is when it is increasing and the third quarter moon is decreasing

Hope this helped! :)

7 0

3 years ago

How did the building of granaries indicate that Harappan civilization was economically strong?

kvasek [131]

It showed that the richest Harappan citizens had excess food to trade or sell. It showed that Harappa could store excess food to save, sell, or trade with others.

5 0

3 years ago

H2(g) + F2(g)2HF(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.20 moles

abruzzese [7]

Answer: The value of $\Delta S^o$ for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

Explanation:

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$H_2(g)+F_2(g)\rightarrow 2HF(g)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(HF(g))})]-[(1\times \Delta S^o_{(H_2(g))})+(1\times \Delta S^o_{(F_2(g))})]$

We are given:

$\Delta S^o_{(HF(g))}=173.78J/K.mol\\\Delta S^o_{(H_2)}=130.68J/K.mol\\\Delta S^o_{(F_2)}=202.78J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (173.78))]-[(1\times (130.68))+(1\times (202.78))]\\\\\Delta S^o_{rxn}=14.1J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(14.1) J/K = -14.1 J/K

We are given:

Moles of hydrogen gas reacted = 2.20 moles

By Stoichiometry of the reaction:

When 1 mole of hydrogen gas is reacted, the entropy change of the surrounding will be -14.1 J/K

So, when 2.20 moles of hydrogen gas is reacted, the entropy change of the surrounding will be = $\frac{-14.1}{1}\times 2.20=-31.02J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

7 0

3 years ago

when particles of matter are in direct contact and movement occurs in the substance due to convection, thermal energy transfers

liq [111]

Thermal energy transfers in a solid state, due to convection, in metalic substances.

This is because the covalent bonds between the atoms are being broken and reformed again while the metal is experiencing stress. covalent bonds store energy.

4 0

3 years ago