I think one of the signs is <span>water and salt are formed
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Answer:
I'd say "a" because not everything with plants and animals is perfectly organized together nothing ever is.
First, we have to see how K2O behaves when it is dissolved in water:
K2O + H20 = 2 KOH
According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:
c(KOH) : c(K2O) = 1 : 2
So,
c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)
Now we can calculate pH:
pOH= -log c(OH⁻) = -log 0.01 = 2
pH= 14-2 = 12
Answer: The molar enthalpy change is 73.04 kJ/mol
Explanation:
moles of HCl=
As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.
volume of water = 100.0 ml + 50.0 ml = 150.0 ml
density of water = 1.0 g/ml
mass of water =
q = heat released
m = mass = 150.0 g
c = specific heat =
= change in temperature =
Thus 0.0415 mol of HCl produces heat = 3031.3 J
1 mol of HCL produces heat =
Thus molar enthalpy change is 73.04 kJ/mol