You can determine the hazards of these chemicals by looking at their material data safety sheets (MSDS).
1. 0.1 M Ag⁺: Silver compounds are absorbed by skin causing bluish pigmentation. Thus, it <em>causes </em><span><em>staining on skin</em>.</span> Also, liquid <em>vapor may be irritating</em> to skin and also <em>moderately toxic when ingested</em>.
2. 0.1 M Ba²⁺: This is <em>mildly toxic when ingested</em> causing stomach irritation, muscle weakness, swelling of organs like brain, liver, kidney and heart.
3. 0.1 M Fe³⁺:Iron is <em>corrosive, has irritating vapor especially to the eyes, and toxic if ingested</em>.
4. 6 M HCl: This is a concentrated strong acid, so it is <em>corrosive, has irritating vapors, flammable and toxic when ingested</em>.
5. 6 M H₂SO₄: This is also a concentrated strong acid. Moreover, it is a strong oxidizing agent. So, its hazards include: <span><em>corrosive, has irritating vapors, toxic when ingested and causes staining on skin</em>.
</span>6. 6 M HNO₃: This is a concentrated strong acid, so it is <em>corrosive, has irritating vapors, flammable and toxic when ingested</em>.
7. 7.5 M NH₃: This is a weak base. It is characterized for its pungent odor. This is <em>corrosive, has irritating vapors, toxic if ingested, and flammable</em>.
Answer:
From what i've learned so far, the correct answer is "Heat at a constant Pressure" or "Specific Heat"
Explanation:
Hope this helps!
Cross-section of a metal wire wrapped in plastic insulation the metal wire is an element.
<h3>What is an element?</h3>
An element is a substance or material that cannot be affected by an external substance or cannot be broken down by any reaction.
Metal wire is serving as an element, it should not be easily broken or penetrated as an insulator.
Therefore, Cross-section of a metal wire wrapped in plastic insulation the metal wire is an element.
Learn more on element here,
brainly.com/question/18096867
Answer:
Option (B) 7
Explanation:
C3H6O2(l) + O2(g) → CO2(g) + H2O(l)
To know the coefficient of O2 in the above equation, let us balance the equation.
The above equation can be balance as follow:
C3H6O2(l) + O2(g) → CO2(g) + H2O(l)
There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:
C3H6O2(l) + O2(g) → 3CO2(g) + H2O(l)
There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:
C3H6O2(l) + O2(g) → 3CO2(g) + 3H2O(l)
There are a total of 4 atoms of O on the left side and a total of 9 atoms on the right side. It can be balance by putting 7/2 in front of O2 as show below:
C3H6O2(l) + 7/2O2(g) → 3CO2(g) + 3H2O(l)
Multiply through by 2
2C3H6O2(l) + 7O2(g) → 6CO2(g) + 6H2O(l)
Now, the equation is balanced.
From the balanced equation above, the coefficient of O2 is 7.
