Draw the product formed when the alcohol is oxidized with k2cr2o7. in some cases, no reaction occurs (if so, draw the given alco
hol). ch3(ch2)6ch2oh
1 answer:
The given alcohol is octanol. It is a primary alcohol and will easily get oxidized in presence of strong oxidizing agent potassium dichromate.
The reaction is shown in the diagram below. The carbon bearing hydroxyl group will oxidized.
octanol will be oxidized completely to octanoic acid. It it would be tertiary alcohol which is hard to oxidized easily.
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