Answer: The energy of activation for the chirping process is 283.911 kJ/mol
Explanation:
According to the Arrhenius equation,
The expression used with catalyst and without catalyst is,
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= rate of reaction at 
= 194/min
= rate of reaction at 
= 47.6 /min
= activation energy
R = gas constant = 8.314 J/Kmol
tex]T_1[/tex] = initial temperature = 
tex]T_1[/tex] = final temperature = 
Now put all the given values in this formula, we get
![\frac{194}{47.6}=\frac{E_a}{2.303\times 8.314}[\frac{1}{278}-\frac{1}{301}]](https://tex.z-dn.net/?f=%5Cfrac%7B194%7D%7B47.6%7D%3D%5Cfrac%7BE_a%7D%7B2.303%5Ctimes%208.314%7D%5B%5Cfrac%7B1%7D%7B278%7D-%5Cfrac%7B1%7D%7B301%7D%5D)
Thus the energy of activation for the chirping process is 283.911 kJ/mol
Answer:
26.2g = Mass of water in the calorimeter
Explanation:
The heat absorbed for the water is equal to the heat released for the metal. Based on the equation:
Q = m*C*ΔT
<em>Where Q is heat, m is the mass of the sample, C is specific heat of the material and ΔT is change in temperature</em>
<em />
Replacing we can write:
13.9g * 0.449J/g°C * (54.2°C-15.6°C) = m(H₂O) * 4.184J/g°C * (15.6°C-13.4°C)
240.9J = m(H₂O) * 9.2J/g
<h3>26.2g = Mass of water in the calorimeter</h3>
ML. is the abbreviation of Milliliter
Answer:
The parcial pressure of N₂ in the mixture is 1.24 atm.
Explanation:
The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:
PT = PA + PB
This relationship is due to the assumption that there are no attractive forces between the gases.
In this case:
PT=PHe + PNe + PN₂
You know:
- PT= 1.943 atm
- PHe= 0.137 atm
- PNe= 0.566 atm
- PN₂= ?
Replacing:
1.943 atm= 0.137 atm + 0.566 atm + PN₂
Solving:
1.943 atm= 0.703 atm + PN₂
1.943 atm - 0.703 atm= PN₂
1.24 atm= PN₂
<u><em>The parcial pressure of N₂ in the mixture is 1.24 atm.</em></u>
#1 is 95L balanced . #2 is 55^3G balanced.
