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olga_2 [115]
3 years ago
12

Help plzzzzzzzzzz ASAP!!!

Chemistry
2 answers:
umka21 [38]3 years ago
8 0
B.) Index of refraction of the second medium is higher
Ksenya-84 [330]3 years ago
3 0
The answer is the second on or B to be precise
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7 0
2 years ago
ASAP HELP ME PLEASE!!!!!!<br><br> what is the difference in an element and a compounds?
Bas_tet [7]

Answer:

ELEMENTS

COMPOUNDS

Elements are made up of one kind of atoms.

Compounds are made up of two or more kinds of atoms.

Elements cannot be broken down into simpler substances by any physical or chemical method.

Compounds can be broken down into simpler substances by chemical methods.

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7 0
3 years ago
Read 2 more answers
en un recipiente se tiene 800 g de una solución al 35% en masa de ácido sulfuroso, de la cual se evapora 80ml de agua. ¿cuál es
Alinara [238K]

The mass percent of sulfurous acid in the new solution : 38.9%

<h3>Further explanation</h3>

<em>In a container you have 800 g of a 35% by mass solution of sulfurous acid, from which 80 ml of water evaporates. What is the mass percent of sulfurous acid in the new solution? data: density of water is 1g / ml.</em>

<em />

solution 1

composition :

  • 35% acid :

\tt 0.35\times 800~g=280~g

  • water :

\tt 800-280=520~g

solution 2(new solution)

composition :

  • water

\tt 520-(80~ml\times 1~g/ml)=440~g

  • Total mass of new solution after water evaporated

\tt 280(acid)+440(water)=720~g

  • %mass of acid in a new solution

\tt \dfrac{280}{720}\times 100\%=38.9\%

5 0
2 years ago
Which of thes is a property of a substance that is composed of atoms that are held together by ionic bonds?
Svetlanka [38]

Answer: D) It conducts electricity when it is dissolved in water

8 0
1 year ago
The activation energy for proline isomerization of a peptide depends on the identity of the preceding residue and obeys Arrheniu
MAVERICK [17]

Answer:

Activation energy of phenylalanine-proline peptide is 66 kJ/mol.

Explanation:

According to Arrhenius equation-     k=Ae^{\frac{-E_{a}}{RT}}    , where k is rate constant, A is pre-exponential factor, E_{a} is activation energy, R is gas constant and T is temperature in kelvin scale.

As A is identical for both peptide therefore-

                                   \frac{k_{ala-pro}}{k_{phe-pro}}=e^\frac{[E_{a}^{phe-pro}-E_{a}^{ala-pro}]}{RT}

Here \frac{k_{ala-pro}}{k_{phe-pro}}=\frac{0.05}{0.005} , T = 298 K , R = 8.314 J/(mol.K) and E_{a}^{ala-pro}=60kJ/mol

So, \frac{0.05}{0.005}=e^{\frac{[E_{a}^{phe-pro}-(60000J/mol)]}{8.314J.mol^{-1}.K^{-1}\times 298K}}

   \Rightarrow E_{a}^{phe-pro}=65705J/mol=66kJ/mol (rounded off to two significant digit)

So, activation energy of phenylalanine-proline peptide is 66 kJ/mol

7 0
3 years ago
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