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Elis [28]
3 years ago
11

the empirical formula of a compound is CH3O. What is the molecular formula if the mass is 62.0g/mole?

Chemistry
1 answer:
zalisa [80]3 years ago
5 0
The empirical formula is the simplest number of atoms each can be reduced to. If we want to find the molecular formula, we need to find the right number of atoms of each that will add to the given mass, in this case, 62.0 grams. In this case, we find the individual masses of each element.
Carbon: 12.011 grams

Hydrogen: 1.008 grams * 3 since there are three

Oxygen: 15.999 grams

When we add these, we get a total mass of 31.034 grams. If we multiply it by two, we get the exact mass of the molecule formula, 62.068. Since we multiplied by two, all molecules have to be multiplied by two. That just means we multiply the number of molecules in the compound by two.
Therefore,

Empirical: CH3O

CH3O*2= C2H6O2 = Molecular
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What is the empirical formula for a compound that is 83.7% carbon and 16.3% hydrogen?
zubka84 [21]
Hello!

We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100 g solution)

C: 83.7% = 83,7 g 
H: 16.3% = 16.3 g 

Let us use the above mentioned data (in g) and values will be ​​converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:

C:  \dfrac{83.7\:\diagup\!\!\!\!\!g}{12\:\diagup\!\!\!\!\!g/mol} \approx 6.975\:mol

H: \dfrac{16.3\:\diagup\!\!\!\!\!g}{1\:\diagup\!\!\!\!\!g/mol} = 16.3\:mol

We note that the values ​​found above are not integers, so let's divide these values ​​by the smallest of them, so that the proportion is not changed, let's see:

C:  \dfrac{6.975}{6.975} = 1

H:  \dfrac{16.3}{6.975} \approx 2.3

Note: So the ratio in the smallest whole numbers of carbon to hydrogen is 3:7, t<span>hus, the minimum or empirical formula found for the compound will be:
</span>
\boxed{\boxed{C_3H_7}}\end{array}}\qquad\checkmark

I hope this helps. =)
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