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Elis [28]
3 years ago
11

the empirical formula of a compound is CH3O. What is the molecular formula if the mass is 62.0g/mole?

Chemistry
1 answer:
zalisa [80]3 years ago
5 0
The empirical formula is the simplest number of atoms each can be reduced to. If we want to find the molecular formula, we need to find the right number of atoms of each that will add to the given mass, in this case, 62.0 grams. In this case, we find the individual masses of each element.
Carbon: 12.011 grams

Hydrogen: 1.008 grams * 3 since there are three

Oxygen: 15.999 grams

When we add these, we get a total mass of 31.034 grams. If we multiply it by two, we get the exact mass of the molecule formula, 62.068. Since we multiplied by two, all molecules have to be multiplied by two. That just means we multiply the number of molecules in the compound by two.
Therefore,

Empirical: CH3O

CH3O*2= C2H6O2 = Molecular
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Carbon dioxide and water react to form methanol and oxygen, like this:
fredd [130]

Answer:

24x10³

Explanation:

2CO₂(g) + 4H₂O(g) → 2CH₃OH(l) + 3O₂ (g)

The equilibrium constant for this reaction is:

Kc = \frac{[O_2]^3}{[CO_2]^2[H_2O]^4}

The expression of [CH₃OH] is left out as it is a pure liquid.

Now we <u>convert the given masses of the relevant species into moles</u>, using their <em>respective molar masses</em>:

  • CO₂ ⇒ 3.28 g ÷ 44 g/mol = 0.0745 mol CO₂
  • H₂O ⇒ 3.86 g ÷ 18 g/mol = 0.214 mol H₂O
  • O₂ ⇒ 2.80 g ÷ 32 g/mol = 0.0875 mol O₂

Then we calculate the concentrations:

  • [CO₂] = 0.0745 mol / 7.5 L = 0.0099 M
  • [H₂O] = 0.214 mol / 7.5 L = 0.0285 M
  • [O₂] = 0.0875 mol / 7.5 L = 0.0117 M

Finally we <u>calculate Kc</u>:

  • Kc = \frac{0.0117^3}{0.0099^2*0.0285^4} = 24x10³

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I think the answer for #3 is A not 100% sure but hope I can help!
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