Identify the name of the smallest particle of an element that still retains all the chemical properties of that element?

Chloroform is a liquid once used for anesthetic. What is the volume of 5.0 g of chloroform? The density of chloroform 1.49 g/mL

mario62 [17]

Answer:

3.3557047 mL

Explanation:

The density can be found using the following formula:

$d=\frac{m}{v}$

Let's rearrange the formula to find the volume, $v$ .

$d*v=\frac{m}{v}*v$

$d*v=m$

$\frac{d*v}{d} =\frac{m}{d}$

$v=\frac{m}{d}$

The volume can be found by dividing the mass by the density. The mass of the chloroform is 5 grams and the density is 1.49 grams per milliliter. Therefore,

$m= 5g \\d= 1.49 g/mL$

Substitute the values into the formula.

$v=\frac{5g}{1.49 g/mL}$

Divide. When we divide, the grams, or g, in the numerator and denominator will cancel out.

$v= \frac{5}{1.49}mL$

$v=3.3557047 mL$

The volume of 5 grams of chloroform is 3.3557047 milliliters

4 0

3 years ago

What is the final, balanced equation that is formed by combining these two half reactions?

lara31 [8.8K]

Answer: Balanced equation that is formed by combining these two half reactions is $Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O$ .

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, $Cu \rightarrow Cu^{2+} + 2e^{-}$

$NO^{-}_{3} + 2e^{-} + 2H^{+} \rightarrow NO^{-}_{2} + H_{2}O$

On cancelling the common species from both these half-reactions, the complete balanced equation will be as follows.

$Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O$

Thus, we can conclude that balanced equation that is formed by combining these two half reactions is $Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O$ .

7 0

3 years ago

What does the 3 indicate in 1s22s22p63s1?

Dahasolnce [82]

The 3 indicates the third electron shell. (Which has only 1 electron in it in this configuration)

Hope this helps! :)

6 0

3 years ago

Read 2 more answers

A radioactive element reduces to 5.00% of its initial mass in

Stolb23 [73]

The half-life in months of a radioactive element that reduce to 5.00% of its initial mass in 500.0 years is approximately 1389 months

To solve this question, we'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

Amount remaining (N) = 5%

Original amount (N₀) = 100%

<h3>Number of half-lives (n) =?</h3>

N₀ × 2ⁿ = N

5 × 2ⁿ = 100

2ⁿ = 100/5

2ⁿ = 20

Take the log of both side

Log 2ⁿ = log 20

nlog 2 = log 20

Divide both side by log 2

n = log 20 / log 2

Thus, 4.32 half-lives gas elapsed.

Finally, we shall determine the half-life of the element. This can be obtained as follow.

Number of half-lives (n) = 4.32

Time (t) = 500 years

t½ = t / n

t½ = 500 / 4.32

t½ = 115.74 years

Multiply by 12 to express in months

t½ = 115.74 × 12

<h3>t½ ≈ 1389 months </h3>

Therefore, the half-life of the radioactive element in months is approximately 1389 months

Learn more: brainly.com/question/24868345

8 0

2 years ago

At the most basic level, in order to produce oxygen and a carbohydrate (comprised of carbon, hydrogen, and oxygen), carbon dioxi

Kaylis [27]

At the most basic level, in order to produce oxygen and a carbohydrate (comprised of carbon, hydrogen, and oxygen), carbon dioxide must react with water as a source of hydrogen.

In order to construct carbohydrate molecules (often glucose) and release oxygen into the atmosphere, photosynthesis utilises carbon dioxide and water. Photosynthesis occurs in organelles called chloroplasts found in eukaryotic autotrophs like plants and algae.

Commonly used notation for photosynthesis is:

6CO $_{2}$ + 6H $_{2}$ O C $_{6}$ H $_{12}$ O $_{6}$ + 6O $_{2}$

This indicates that the reactants, six carbon dioxide molecules and six water molecules, are transformed into a sugar molecule and six oxygen molecules, the products, by light energy being absorbed by chlorophyll.

Learn more about water here:

brainly.com/question/16630851

#SPJ4

8 0

2 years ago