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Natasha2012 [34]
3 years ago
15

If J = 12 then J/3 + 3 What is J

Mathematics
2 answers:
Ray Of Light [21]3 years ago
7 0
Well i think your asking what is J divided by 3+3 which is 4+3 =7 or IF multiplying which is 36 +3= 39
kolbaska11 [484]3 years ago
6 0
Well, you're given that J=12. I think the extra information is extraneous, unless there's something more that you forgot to add.
Hope I could be of some assistance. :)
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<em>1.</em> <em>Circle A and circle A', have the same circumference.</em> <em>(Yes)</em>

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3 years ago
Triangle pqr has vertices p(-3 -1) q(-1,-7) and r(3,3) and points a and b are midpoints of segment pq and segment rq respectivel
Serhud [2]

Answer:

View graph

Step-by-step explanation:

Be:   p(-3,-1)   q(-1,-7)   r(3,3)

we must find the value of the middle point a and b

a=\frac{pq}{2}\\b=\frac{rq}{2}

remember that distance between two points is:

d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }

pq=distance between p and q

qr =distance between q and rpq=\sqrt{(-1+3)^{2}+(-7+1)^{2}}=\sqrt{(2)^{2}+(-6)^{2}}=\sqrt{40}\\ pq=2\sqrt{10}\\ a=\frac{pq}{2}=\frac{2\sqrt{10}}{2}=\sqrt{10}\\  coordinates\\a=\frac{pq}{2}=\frac{(-3-1,-7-1)}{2}=(-2,-4)\\\\qr=\sqrt{(3+1)^{2}+(3+7)^{2}}=\sqrt{(4)^{2}+(10)^{2}}=\sqrt{116}\\qr=2\sqrt{29}\\ b=\frac{qr}{2}=\frac{2\sqrt{29}}{2}=\sqrt{29}\\  coordinates\\b=\frac{pq}{2}=\frac{(-1+3,-7+3)}{2}=(1,-2)\\

ab is parallel to pr if slope ab is equal to slope pr

m_{ab}=\frac{-2+4}{1+2}=\frac{2}{3}\\m_{pr}=\frac{3+1}{3+3}=\frac{2}{3}\\ m_{ab}=m_{pr}

finally distance ab is equal to distance pr/2

d_{ab=}\sqrt{(-2+4)^{2}+(1+2)^{2}}=\sqrt{13}\\ d_{pr=}\sqrt{(3+1)^{2}+(3+3)^{2}}=\sqrt{52}\\ d_{ab=}\frac{d_{pr}}{2}

8 0
3 years ago
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