Consider a comparison of two models. The "complete" model has both curvature and interaction. The "reduced" model has curvature,
1 answer:
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A motorist drove 150 miles in the morning and;
50 miles in the afternoon
His average rate in the morning was twice his average rate in the afternoon
He spent 5hrs driving
Let the times spent driving in the morning be x
Average speed = Distance ÷ time
= 2(
)
Cross multiplying gives;
750 - 150x = 100x
250x = 750 , x =3
Average speed in the morning is 150/3 = 50miles/hr
Average speed in the afternoon = 50/(5-3) = 25miles/hr
The <u>correct answer</u> is:
$5,000.
Explanation:
When it is first purchased, the depreciation expense is calculated using the formula:
The cost was $23,000; the salvage value was $3,000; and the useful life was 8 years:
This means the value of the vehicle depreciates $2500 per year.
After 4 years, the vehicle would depreciate 2500(4) = $10,000.
This makes the new value $23000-$10000 = $13000.
Reevaluating the depreciation expense at this point, we use $13000 for the "cost" (current value), $3000 is still the salvage value, and now the total useful life was 6; we take 4 off of this, since it has already been 4 years:
The depreciation expense in year 5 is $5,000.
$5,000.
Explanation:
When it is first purchased, the depreciation expense is calculated using the formula:
The cost was $23,000; the salvage value was $3,000; and the useful life was 8 years:
This means the value of the vehicle depreciates $2500 per year.
After 4 years, the vehicle would depreciate 2500(4) = $10,000.
This makes the new value $23000-$10000 = $13000.
Reevaluating the depreciation expense at this point, we use $13000 for the "cost" (current value), $3000 is still the salvage value, and now the total useful life was 6; we take 4 off of this, since it has already been 4 years:
The depreciation expense in year 5 is $5,000.