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Mamont248 [21]
3 years ago
5

Which of the following would be found in both eukaryotic AND prokaryotic cells?

Chemistry
2 answers:
beks73 [17]3 years ago
7 0
Nucleus ,endoplasmic reticulum
ladessa [460]3 years ago
7 0

Answer:

A.

Explanation:

the Nucleus and Endoplasmic Reticulum are both found in both eukaryotic and prokaryotic cells, but the necleus is the more common answer.

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Temperature (°C)
Andreyy89
The answer is the solution saturated than more dissolved with is C
5 0
2 years ago
Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p
Butoxors [25]

Answer:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

BiO_3^-\rightarrow Bi^{3+}

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

(Bi^{5+}O_3)^-\rightarrow Bi^{3+}

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Then, we accommodate the waters to obtain:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Best regards!

7 0
3 years ago
Nitrifying bacteria participate in the nitrogen cycle mainly by
Brilliant_brown [7]
Hello, here’s the answer to your question. Converting ammonia to nitrate, which is absorbed by plants
6 0
3 years ago
Calculate the number of O atoms in 0.150 g of CaSO4 · 2H2O.
natulia [17]

Answer:

There are 0.00523 moles of oxygen in 0.150 grams of calcium sulfate crystal.

Explanation:

Mass of calcium sulfate crystal = m = 0.150 g

Molar mass of calcium sulfate crystal = M = 172 g/mol

Moles of magnesium nitrate = n

n=\frac{m}{M}

n=\frac{0.150 g}{172 g/mol}=0.0008721 mol

1 mole of calcium sulfate crystal has 6 moles of oxygen atoms. Then 0.004446 moles calcium sulfate crystal will have :

6\times 0.0008721 mol=0.0052326mol\approx 0.00523 mol

There are 0.00523 moles of oxygen in 0.150 grams of calcium sulfate crystal.

8 0
3 years ago
HELP ASAP!!! #2 only please.
shtirl [24]

Answer:

friend me on here and imma send you the link Explanation:

6 0
3 years ago
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