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morpeh [17]
3 years ago
15

What are the materials needed during cell respiration

Chemistry
1 answer:
Dafna1 [17]3 years ago
4 0
Oxygen and glucose are both reactants in the process of cellular respiration. The main product of cellular respiration is ATP; waste products include carbon dioxide and water.
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Calculate the displacement (the total volume of the cylinder through which the piston move) of a 5.70L automobile engine in cubi
Novay_Z [31]

Answer:

348 inches³

Explanation:

From our previous knowledge of  units conversion:

We know that 1000 cm³ makes 1 Liter.

Thus, for  a 5.70 L automobile engine in cubic meters will be:

= 5.70 × 1000 cm³

= 5700 cm³

Now, the displacement of the automobile in cubic inches provided that 1 inch = 2.534 cm is:

⇒ 5700× (1/ (2.54)³) in³

= 5700×0.0610 in³

= 347.7 in³

≅ 348 inches³

4 0
4 years ago
If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?
photoshop1234 [79]
The combustion reaction is as expressed,

                CxHy + O2 --> CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,
       mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g. 

     moles of C = 0.86 g C / 12 g = 0.0713
     moles of H = 0.14 g H / 1 g  = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.
7 0
3 years ago
Which tool was most likely used in a procedure if the lab report shows that approximately 300 mL of water was used ?
Travka [436]

Graduated Cylinder is the answer to this.


4 0
3 years ago
Read 2 more answers
Calculate the number of moles of Na+ ions in 25g of sodium carbonate?​
valkas [14]

Explanation:

First, we need to calculate the number of moles of sodium carbonate we have in a 25 g sample. To calculate this, we will

find the molar mass of sodium carbonate (Na2CO3):

⇒ 2 × Molar mass of sodium + Molar mass of carbon + 3×molar mass of oxygen

⇒ 2 × 23 + 12 + 3 × 16

⇒ 46 + 12 + 48

⇒ 106g/mol

Thus, the molar mass of Na2CO3 is 106g/mol.

Therefore, number of moles = 25 ÷ 106

=> 0.2358 mol

Now, we know that every mole of Na2CO3 have 0.2358 moles of Na+ ions. Hence, total moles of Na2CO3 is 0.4716 moles

Number of ions present = 6.022 × 1023 × 0.4716 mol = 2.84 × 1023ions

6 0
3 years ago
4. How many minutes are there in 1.000 week?<br> please help
ioda
There are 10,080 minutes
5 0
3 years ago
Read 2 more answers
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