T=2 the solution set is t=2
[tex]\dfrac{\dfrac{r-5}{9r}}{\dfrac{5-r}{3r^2}}=\dfrac{r-5}{9r}.\dfrac{-3r^2}{r-5}=\dfrac{-r}{3}[\tex]
The answer is 1/6 because 2/3-1/2 the command denominator is 6 so 2 goes in six 3 times then you do 3×1 =3 so you got 3/6 then you do 3 goes in 6 2 times then you do 2×2=4 and 4-3=1 so you get 1/6
Answer:
Individual package would be 3.83
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