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jeka57 [31]
3 years ago
10

Heat transfer by radiation occurs between two large parallel plates, which are maintained at temperatures T1 and T2, with T1 &gt

; T2. To reduce the rate of heat transfer between the plates, it is proposed that they be separated by a thin shield that has different emissivities on opposite surfaces. In particular, one surface has the emissivity ε s < 0.5, while the opposite surface has an emissivity of 2ε s. (a) How should the shield be oriented to provide the larger reduction in heat transfer between the plates? That is, should the surface of emissivity ε s or that of emissivity 2ε s be oriented toward the plate at T1? (b) What orientation will result in the larger value of the shield temperature Ts?

Physics
1 answer:
Vinil7 [7]3 years ago
6 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

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marusya05 [52]

1).  From the frame of reference of a passenger on the airplane looking out of his window, the tree appears to be moving, at roughly 300 miles per hour toward the left of the picture.

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The ball started out in the child's hand, and it ended up 2 meters away from her in the direction of the wall.  So the displacement of the ball from the beginning to the end of the story is:  2 meters toward the wall.


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3 years ago
True or false questions for work and power.​
dalvyx [7]

Answer:

lo escribes en español?

Explanation:

no hablo ingles

5 0
3 years ago
How do cells use food to make energy and maintain homeostasis?
vladimir1956 [14]

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plz mark me as brainliest :)

7 0
3 years ago
When Earth’s Northern Hemisphere is tilted toward the Sun during June, some would argue that the cause of our seasons is that th
Ludmilka [50]

Answer:

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Explanation:

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4 0
4 years ago
Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters.
VashaNatasha [74]
What a delightful little problem !
Here's how I see it:

When 'C' is touched to 'A', charge flows to 'C' until the two of them are equally charged.  So now, 'A' has half of its original charge, and 'C' has the other half.

Then, when 'C' is touched to 'B', charge flows to it until the two of <u>them</u> are equally charged.  How much is that ?  Well, just before they touch, 'C' has half of an original charge, and 'B' has a full one, so 1/4 of an original charge flows from 'B' to 'C', and then each of them has 3/4 of an original charge.

To review what we have now:  'A' has 1/2 of its original charge, and 'B' has 3/4 of it.

The force between any two charges is:

F = (a constant) x (one charge) x (the other one) / (the distance between them)².

For 'A' and 'B', the distance doesn't change, so we can leave that out of our formula.

The original force between them was  3 = (some constant) x (1 charge) x (1 charge).

The new force between them is  F = (the same constant) x (1/2) x (3/4) .

Divide the first equation by the second one, and you have a proportion:

3 / F  =  1 / ( 1/2 x 3/4 )

Cross-multiply this proportion:

3 (1/2 x 3/4)  = F

F  =  3/2 x 3/4  =  9/8  =  <em>1.125 newton</em>.


That's my story, and I'm sticking to it.
 
5 0
3 years ago
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