Heat transfer by radiation occurs between two large parallel plates, which are maintained at temperatures T1 and T2, with T1 >
; T2. To reduce the rate of heat transfer between the plates, it is proposed that they be separated by a thin shield that has different emissivities on opposite surfaces. In particular, one surface has the emissivity ε s < 0.5, while the opposite surface has an emissivity of 2ε s. (a) How should the shield be oriented to provide the larger reduction in heat transfer between the plates? That is, should the surface of emissivity ε s or that of emissivity 2ε s be oriented toward the plate at T1? (b) What orientation will result in the larger value of the shield temperature Ts?
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Answer:
The fraction of kinetic energy to the total energy is .
Explanation:
displacement is one third of the amplitude.
Let the amplitude is A.
x= A/3
The kinetic energy of the body executing SHM is
The total energy is
Divide (1) by (2)