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kupik [55]
4 years ago
9

Sheena can row a boat at 2.20 mi/h in still water. She needs to cross a river that is 1.20 mi wide with a current flowing at 1.6

0 mi/h. Not having her calculator ready, she guesses that to go straight across, she should head upstream at an angle of 25.0° from the direction straight across the river.
Physics
1 answer:
kicyunya [14]4 years ago
5 0

Answer:

Part a)

v_{bw} = 2.1 mph

Part b)

t = 0.6 h

Part c)

x = 0.4 mile

Part d)

\theta = 46.6 degree

Explanation:

Part a)

Velocity of the boat with respect to water stream is given as

v_{bw} = v_b + v_w

v_{bw} = (1.60 - 2.20sin25) \hat i + 2.20 cos25\hat j

so we have

v_{bw} = 0.67 \hat i + 2 \hat j

magnitude of the speed is given as

v_{bw} = \sqrt{0.67^2 + 2^2}

v_{bw} = 2.1 mph

Part b)

Time to cross the river is given as

t = \frac{y}{v_y}

t = \frac{1.20}{2}

t = 0.6 h

Part c)

Distance moved by the boat in downstream is given as

x = v_x t

x = 0.67 \times 0.6

x = 0.4 mile

Part d)

In order to go straight we must net speed along the stream must be zero

so we will have

vsin\theta = v_w

2.20 sin\theta = 1.60

\theta = 46.6 degree

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