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Rom4ik [11]
3 years ago
9

The two sleds shown below are about to collide. When they collide, they bounce off each other and no energy is lost. The kinetic

energy of sled A is 39,561 J just after the collision. What is the kinetic energy of sled B after the collision? (Note: The potential energy of each sled after the collision is 0 J.)
Options:
A. 25,861 J
B. 11,783 J
C. 7,261 J
D. 6,439 J

Physics
1 answer:
BartSMP [9]3 years ago
3 0

Answer:

Explanation:

Given that,

The potential energy of the slides before collision are

U_a = 13,700 J

U_b = 32,300 J.

Also, the final potential energy of sled B is

V_b = 39,561 J

So, since the body bounce off after collision, then it is elastic collision and in elastic collision, energy is conserved.

So, applying conservation of energy and since no energy is loss, then, total potential energy before collision is equal to total potential energy after collision.

Then,

U_a + U_b = V_a + V_b

13,700 + 32,300 = V_a + 39,561

Then,

V_a = 13,700 + 32,300 - 39,561

V_a = 6439

The correct option is D

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Answer:

1. Nismo: L_{a}=0.1244

2. Ferdinand: L_{a}=0.0796, Shelby: L_{a}=0.0796

3. Enzo: L_{a}=0.0398

4. Lotus: L_{a}=0.0199

Explanation:

The luminosity of a star is the amount of light it emits from its surface. The luminosity is an intrinsic property of the star. Apparent brightness is how bright the star appears to a detector on Earth. Apparent brightness is not an intrinsic property of the star; it depends on the location of the observer.

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Enzo: 200 LSun , 20 ly

L_{a}=\frac{L}{4*pi*D^{2}}

L_{a}=\frac{200}{4*pi*20^{2}}

L_{a}=0.0398

Ferdinand: 400 LSun , 20 ly

L_{a}=\frac{L}{4*pi*D^{2}}

L_{a}=\frac{400}{4*pi*20^{2}}

L_{a}=0.0796

Nismo: 100 LSun , 8 ly

L_{a}=\frac{L}{4*pi*D^{2}}

L_{a}=\frac{100}{4*pi*8^{2}}

L_{a}=0.1244

Lotus: 400 LSun , 40 ly

L_{a}=\frac{L}{4*pi*D^{2}}

L_{a}=\frac{400}{4*pi*40^{2}}

L_{a}=0.0199

Shelby: 100 LSun , 10 ly

L_{a}=\frac{L}{4*pi*D^{2}}

L_{a}=\frac{100}{4*pi*10^{2}}

L_{a}=0.0796

Apparent brightness of stars is summarized as below. Absolute values are considered as units are unspecified

Enzo: L_{a}=0.0398

Ferdinand: L_{a}=0.0796

Nismo: L_{a}=0.1244

Lotus: L_{a}=0.0199

Shelby: L_{a}=0.0796

Organized in order of apparent brightness

1. Nismo: L_{a}=0.1244

2. Ferdinand: L_{a}=0.0796, Shelby: L_{a}=0.0796

3. Enzo: L_{a}=0.0398

4. Lotus: L_{a}=0.0199

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