1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zina [86]
3 years ago
11

A 3.0N force to the right acts on a 0.5kg object at rest during a time interval of 4.0 seconds .What is the velocity of the obje

ct at the end of this interval?
Physics
2 answers:
Mariulka [41]3 years ago
6 0

Answer:

v = 24m/s

Explanation:

To find the velocity of the object you can use the Newton second law, and the formula for the acceleration in an accelerated motion:

F=ma\\\\a=\frac{v_f-v_o}{t}

F: force = 3.0N

a: acceleration

m: mass of the object = 0.5kg

vf: final velocity

vo: initial velocity = 0 m/s

t: time in which the force is applied = 4.0s

From the first equation you can calculate the acceleration of the object. With the value of a you can calculate the final velocity. Hence, by replacing the values of F, m, vo and t you obtain:

a=\frac{F}{m}=\frac{3.0N}{0.5kg}=6\frac{m}{s^2}\\\\v_f=at+v_o=(6\frac{m}{s^2})(4.0s)+0\frac{m}{s}=24\frac{m}{s}

hence, the velocity of the object is 24m/s

monitta3 years ago
5 0

Answer:

24 m/s

Explanation:

Applying Newton's second law of motion,

F = ma................ Equation 1

Where F = force acting on the object, m = mass of the object a = acceleration of the object.

First we calculate for a.

make a the subject of the formula in equation 1 above

a = F/m............... Equation 2

Given: F = 3 N, m = 0.5 kg.

Substitute into equation 2

a = 3/0.5

a = 6 m/s²

Secondly we calculate the velocity by using,

v = u+at................... Equation 3

Where v = Final velocity of the object, u = initial velocity of the object, t = time interval

Given: u = 0 m/s (at rest), a = 6 m/s², t = 4 s

Substitute into equation 3

v = 0+6(4)

v = 24 m/s

You might be interested in
A glass ball of radius 3.74 cm sits at the bottom of a container of milk that has a density of 1.04 g/cm3. The normal force on t
Gelneren [198K]

Answer:

The mass of the ball is 0.23 kg

Explanation:

Given that

radius ,r= 3.74 cm

Density of the milk ,ρ = 1.04 g/cm³ = 1.04  x 10⁻³ kg/cm³

Normal force ,N= 9.03 x 10⁻² N

The volume of the ball V

V=\dfrac{4}{3}\pi r^3

V=\dfrac{4}{3}\times \pi \times 3.74^3\ cm^3

V= 219.13 cm³

The bouncy force on the ball = Fb

Fb = ρ V g

Fb  + N = m g

m=Mass of the ball = Density x volume

m = γ V    , γ =Density of the Ball

ρ V g  + N =  γ V g               ( take g= 10 m/s²)

\gamma =\dfrac{N+\rho V g}{V g}

\gamma =\dfrac{9.03\times 10^{-2}+1.04\times 10^{-3}\times 219.13\times  10}{219.13\times 10}

γ = 0.00108 kg/cm³

m = γ V

m = 0.00108 x 219.13

m= 0.23 kg

The mass of the ball is 0.23 kg

5 0
2 years ago
Consider again the objects you ranked by distance. Suppose each object emitted a burst of light right now. Rank the objects from
Vika [28.1K]

Answer:

Following are the solution to this question:

Explanation:

That light takes a very long time to hit the planet, and the object is far off the earth. The light of such an item near to the planet takes less time to enter it. The star is 2,5 million light-years from the Planet on the far side of the Andromeda Galaxy. But on the other hand, the moon is 15 crore miles from the earth, so sunlight is quickly reached on the ground as the other thing.  

That milky way away from the earth is 66,500 light-years far, that distance between Earth and Orion nebula is 1,344 light-years, with such a distance of 4,367 light-years. The earth is 5.2261 trillion km apart from Pluto.

5 0
2 years ago
Which does not decrease your chances of being injured
Scorpion4ik [409]
C the answer is c please give brainliest
3 0
3 years ago
Did the bigbang violate the law of conservation of energy and matter?
Pie
Under general relativity, there is no 'before the Big Bang'. The problem is that time is itself a part of the universe and is affected by matter and energy. Because of the huge densities just after the Big Bang, time itself is warped in such a way that it cannot go back before that event. It is somewhat like asking what is north of the north pole.

The conservation of matter and energy states that the total amount of mass and energy at one time is the same at any other time. Notice how time is a crucial part of this statement. To even talk about conservation laws, you have to have time.

The upshot is that the Big Bang did not break the conservation laws because time itself is part of the universe and started at the Big Bang and because the conservation laws need to have time in their statements.
3 0
3 years ago
This is a measure of the quantity of matter.
emmainna [20.7K]

The measure of the quantity of matter would be mass. Mass is measured in kilograms. I hope this helped!:)

3 0
3 years ago
Read 2 more answers
Other questions:
  • If a student tried to lift a 350 N box upwards with a lever that is 75 cm long, how much force would they need to provide given
    5·2 answers
  • Enter the expression 2gΔym−−−−−√, where Δ is the uppercase Greek letter Delta.
    9·1 answer
  • According to the octet rule, an atom with two electron shells is most stable when it contains eight
    8·1 answer
  • Select all the facts about a motor
    6·1 answer
  • Leta Stetter Hollingworth conducted pioneering work on __________. A. identity development in ethnic minorities B. cognitive pro
    10·2 answers
  • What is a watt a unit of?<br> power<br><br> distance<br><br> time<br><br> light
    6·2 answers
  • Newton's First Law is:
    6·1 answer
  • 1. What is the sensor that focuses and image in a camera called?
    5·2 answers
  • A ball is dropped from the top of a building. The gravitational force is 10 N down, and the force of air resistance is 1 N up. W
    14·1 answer
  • What is the magnitude of fs on an object lying on a flat surface without moving, on
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!