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velikii [3]
2 years ago
15

H(a) = 2a+ 5g(a) = 3a−5Find h(a)+ g(a)

Mathematics
2 answers:
Alexandra [31]2 years ago
7 0

Answer:

5a

Step-by-step explanation:

h(a) = 2a+ 5

g(a) = 3a−5

h(a)+g(a)

(2a+5)+(3a-5) (substitution)

2a+5+3a-5 (open parentheses)

5a+0 (solve)

5a

never [62]2 years ago
6 0

if

h(a)=2a+5 and g(a)=3a-5 than

h(a)+g(a)=2a+5+3a-5=5a

Answer: h(a)+g(a)=5a

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Explanation
Rounding to the tenth, you look at the 2nd number after the period, if it’s greater than 5 or 5 itself u and 1 to the first number after the period. Back to the question 0.353 , the 2nd number after the period is 5, so u add 1 to the 1st number after the period with it’s 3 and 3+1=4. If you are rounding to tenth only leave one number after the period with gives you 0.4. Hopefully you get it.
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