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shutvik [7]
4 years ago
11

two solutions are boiled. the first is 1 mol of a sodium chloride(nacl) solution forming two ions. the second one is 1 mol of ca

lcium chloride (cacl2) solution forming three ions. how will the boiling points of the two solutions compare? explain your answer.
Chemistry
2 answers:
UkoKoshka [18]4 years ago
5 0

Answer:

1.5 mol ions

Explanation:

svet-max [94.6K]4 years ago
4 0
It will be different according to how each of them is easily warmed up when using thermal energy. 
Water heats at 100 celsius and all the other solutions have slightly different boiling points

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erosion and weathering.

erosion as in breaking it down, weathering is also a cause of erosion, but in the case of rain, it would carry away the remaining sediments.

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In general, the energy needed to remove an electron (the ionization energy) increases as the atomic number increases across a period.

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Calculate ΔH⁰298 (in kJ) for the process P(s) + 5/2 Cl2(g) → PCl5(g) from the following information.
Viefleur [7K]

Answer:

\Delta H_{298}^{0} for the process is -375 kJ

Explanation:

  • Given reaction is a combination of the two given elementary steps.
  • Summation of change in standard enthalpy (\Delta H_{298}^{0})of the two elementary reactions give \Delta H_{298}^{0} of the reaction P(s)+\frac{5}{2}Cl_{2}(g)\rightarrow PCl_{5}(g).

P(s)+\frac{3}{2}Cl_{2}(g)\rightarrow PCl_{3}(g)......\Delta H_{1}=-287kJ

PCl_{3}(g)+Cl_{2}(g)\rightarrow PCl_{5}(g)......\Delta H_{2}=-88kJ

-----------------------------------------------------------------------------------------------------

P(s)+\frac{5}{2}Cl_{2}(g)\rightarrow PCl_{5}(g)

\Delta H_{298}^{0} = \Delta H_{1}+\Delta H_{2}=-287kJ-88kJ=-375kJ

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It's at the very end of the periodic table

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