<span>NaOH + HCl → NaCl + H2O
1 mol 1 mol
</span>2.75 × 10⁻⁴ mol 2.75 × 10⁻⁴ mol
M(H2O) = 2*1.0 +16.0 = 18.0 g/mol
2.75 × 10⁻⁴ mol H2O * 18.0 g H2O/1 mol H2O = 4.95*10⁻³ g H2O
Answer:
Explanation:
Unclear question.
I infer you want a clear rendering, which reads;
A 258.4 g sample of ethanol (C2H5OH) was burned in a calorimetric pump using a Dewar glass. As a consequence, the water temperature rose to 4.20 ° C.
If the heat capacity of the water and the surrounding glass was 10.4 kJ / ° C, calculate the heat of combustion of one mole of ethanol.
I believe it’s 2? Because it’s saying read the temperature. Which is basically saying look at what state the water is in. Ex: hot or cold
Answer:
0.67 mole/litre
Explanation:
the molarity equall no. of moles ÷ volume of sol.
A. The concentration is in mol/L
