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sineoko [7]
4 years ago
9

Solve the equation by taking the square root 4(x+1)^2=100

Mathematics
1 answer:
ELEN [110]4 years ago
5 0

Answer:

Step-by-step explanation:

4(x+1)²=100

(x+1)²= 5²

(x+1)²- 5² = 0

(x+1-5)(x+1+5) = 0  by identity : a² - b ² = (a - b) (a+b)

(x - 4 ) (x+6) =0

x - 4 = 0 or x+6 = 0

x = 4  or x = - 6

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Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6, with a different number appea
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Answer:

0.2

Step-by-step explanation:

If two number cubes as tossed then the total possible out comes are

Total = {(1,1),(2,1),(3,1),(4,1),(5,1),(6,1),(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,3),(2,3),(3,3),(4,3),(5,3),(6,3),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,5),(2,5),(3,5),(4,5),(5,5),(6,5),(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}

Number of elements in sample space are

n(S)=36

Let A and B represent the following events.

A = The sum will be 4.

A = {(1,3),(2,2),(3,1)}

n(A) = 3

B = The sum is less than or equal to 6.

B = {(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)}

n(B)=15

Intersection of both events is

A∩B = {(1,3),(2,2),(3,1)}

n(A∩B) = 3

P(A)=\dfrac{n(A)}{n(S)}=\dfrac{3}{36}

P(B)=\dfrac{n(B)}{n(S)}=\dfrac{15}{36}

P(A\cap B)=\dfrac{n(A\cap B)}{n(S)}=\dfrac{3}{36}

We need to find the probability that the sum will be 4, given that the sum is less than or equal to 6.

P(\frac{A}{B})=\dfrac{P(A\cap B)}{P(B)}

P(\frac{A}{B})=\dfrac{\frac{3}{36}}{\frac{15}{36}}

P(\frac{A}{B})=\dfrac{3}{15}

P(\frac{A}{B})=\dfrac{1}{5}

P(\frac{A}{B})=0.2

Therefore, the required probability is 0.2.

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3 years ago
Mark got 54 out of 66 in his maths test how many did he get wrong. Give your answer in its simplest form
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Answer:

9/11 I think!

Step-by-step explanation:

54/66= 9/11

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