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nexus9112 [7]
2 years ago
13

What is the solution to this system of equations: y=5x+10 and y=-3x+90?

Mathematics
1 answer:
KonstantinChe [14]2 years ago
4 0

Answer:

x=88

y=420

Step-by-step explanation:

Multiply the first equation by 3 and the second by 5 to cancel out.

y=15x+30\\y=-15x+450\\y=420\\

Now plug y into one of the original equations.

y=5x+10\\450=5x+10\\440=5x\\x=88

Hope this helps! <3

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Given f ( x ) = 3 x 2 + k x − 13 f(x)=3x 2 +kx−13, and the remainder when f ( x ) f(x) is divided by x + 4 x+4 is 15 15, then wh
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k=5

Step-by-step explanation:

We are provided with function, f ( x ) = 3 x^{2} + kx − 13

which is divided by x+4 gives 15.

Here,

since f(x) is divided by x+4 so we can put :

x+4 = 0

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Putting this in f(x) -----> f(-4)

f(x) = f(-4) = 3 (-4^{2}) + k(-4) − 13

f(-4) = 3(16) - 4k - 13

f (-4) = 48 - 4k - 13                ------------------------------------------Equation 1

Since, when f(x) is divided by x+4 , the remainder is 15 so we can say,

f(-4) = 15

putting in equation 1

f (-4) = 15 = 48 - 4k - 13

48 -4k - 13 = 15

35 - 4k = 15                      

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or 20 = 4k

or 4k = 20

k = \frac{20}{4}

<h2>k = 5</h2>

4 0
3 years ago
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